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Force on a current-carrying wire, force between parallel currents, and the current loop as a magnetic dipole sheet
3-mark answer frame

Derive an expression for the force per unit length between two long straight parallel wires carrying currents. Use it to define one ampere.

How to lay out the answer. Follow the frame, then write it in your own words.

  1. 1 · Start from the field of a wire. Wire 1 makes B₁ = μ₀I₁/2πr at wire 2, at right angles to it.
  2. 2 · Draw the wires. [Two vertical wires r apart with upward currents I₁ and I₂; B₁ shown as ⊗ at wire 2; the force on each wire pointing towards the other]
  3. 3 · Find the force. A length l of wire 2 feels F = B₁I₂l = μ₀I₁I₂l/2πr, so F/l = μ₀I₁I₂/2πr.
  4. 4 · Give the direction. By Fleming's left-hand rule, currents in the same direction attract and opposite currents repel.
  5. 5 · Define the ampere. With I₁ = I₂ = 1 A and r = 1 m, F/l = 2 × 10⁻⁷ N m⁻¹. One ampere is the current in each wire that gives this force.
  6. 6 · Close in one line. So, the force depends on the product of the currents and falls as the distance grows.

Scoring tip: In the definition, say 'long, straight, parallel', '1 m apart', 'in vacuum' and '2 × 10⁻⁷ N per metre'. Each phrase carries marks.