Prove that the tangent at any point of a circle is perpendicular to the radius through the point of contact.
How to lay out the answer. Follow the frame, then write it in your own words.
1 · Write what is given and what is to be found Given: a circle with centre O and a tangent XY at the point P. To prove: OP ⟂ XY.
2 · Draw the figure Circle with centre O; tangent XY touching it at P; any point Q on XY; join OQ, cutting the circle at R.
3 · Construction Take a point Q on XY other than P and join OQ.
4 · Show that Q lies outside If Q were inside or on the circle, XY would meet the circle twice and be a secant. So Q is outside, and OQ meets the circle at R.
5 · Compare the lengths OQ = OR + RQ > OR, and OR = OP (radii). So OQ > OP for every Q ≠ P.
6 · Conclude OP is the shortest distance from O to XY. The shortest segment from a point to a line is perpendicular to it. So OP ⟂ XY.
7 · Check and box the answer Write 'Hence proved' and box it.
Scoring tip: Write Given, To prove and Construction as separate headings. In a 3-mark proof the figure and these headings usually earn the first mark.