State Raoult's law for a solution of two volatile liquids. Derive the expression for the total vapour pressure and draw the graph of vapour pressure against mole fraction for an ideal solution.
How to lay out the answer. Follow the frame, then write it in your own words.
1 · State the law. For a solution of volatile liquids, the partial vapour pressure of each component is directly proportional to its mole fraction.
2 · Write it for each component. p₁ = p₁° x₁ and p₂ = p₂° x₂, where p° is the vapour pressure of the pure liquid.
4 · Substitute x₁ = 1 − x₂.p_total = p₁° + (p₂° − p₁°) x₂, a straight line between p₁° and p₂°.
5 · Draw the graph. Composition on the x-axis (x₁ from 1 to 0, x₂ from 0 to 1) and vapour pressure on the y-axis. Three straight lines: p₁ falling from p₁° to 0, p₂ rising from 0 to p₂°, and p_total joining p₁° to p₂°. Label all three.
6 · Add the vapour composition. y₁ = p₁ ÷ p_total; the vapour is richer in the more volatile component.
7 · Close in one line. So in an ideal solution, the total vapour pressure lies between the two pure vapour pressures and changes linearly with composition.
Scoring tip: Draw the three lines with a ruler and label p₁°, p₂°, p₁, p₂ and p_total. An unlabelled graph loses its mark.