How will you convert: (i) 4-nitrotoluene to 4-methylbenzoic acid (ii) benzene to 3-chlorophenol (iii) propanoic acid to ethanamine (iv) 4-methylaniline to 3,5-dibromotoluene? Give one test to distinguish aniline from propan-1-amine.
How to lay out the answer. Follow the frame, then write it in your own words.
1 · Plan by counting carbons. (i) adds one carbon on the ring (CN). (iii) loses one carbon (Hoffmann). (ii) and (iv) change ring groups through the diazonium salt.
2 · 4-Nitrotoluene to 4-methylbenzoic acid. Sn/HCl → 4-methylaniline → NaNO₂ + HCl, 273 to 278 K → CuCN/KCN (Sandmeyer) → 4-CH₃C₆H₄CN → H₃O⁺ → 4-CH₃C₆H₄COOH.
5 · 4-Methylaniline to 3,5-dibromotoluene. Br₂ water → 2,6-dibromo-4-methylaniline → NaNO₂ + HCl, 273 to 278 K → H₃PO₂ (hypophosphorous acid) → 3,5-dibromotoluene.
6 · Distinguish aniline and propan-1-amine. Diazotise in the cold and add alkaline 2-naphthol: aniline gives an orange-red dye; propan-1-amine gives N₂ gas and no dye.
7 · Close in one line. So Hoffmann, nitriles and diazonium salts together let you build almost any amine or aromatic compound.
Scoring tip: Write each step on its own arrow and give the temperature 273 to 278 K every time you diazotise.