Electric current, free electrons and drift velocity
Current is the rate of flow of charge, I = Δq/Δt. Free electrons drift slowly against the field, giving I = nAev_d.
Free and bound electrons, and current
In an atom, electrons are held to the nucleus by electric attraction. The outermost (valence) electrons are held most weakly. In a metal they leave their atoms and move freely through the solid: these are free electrons. The inner electrons stay bound to their atoms. A potential difference across a wire sets up an electric field inside it, and the free electrons move against the field. This flow of charge is an electric current: the rate of flow of charge through a cross-section, I = Δq/Δt, or I = dq/dt if it changes. Its unit is the ampere: 1 A = 1 C s⁻¹. By convention, current flows the way a positive charge would move, which is opposite to the electron flow. In semiconductors, both electrons and holes carry current.
Derivation: drift velocity v_d = eEτ/m
A wire has free electrons, each of charge e and mass m. A field E acts inside it.
- 1With no field, the free electrons dash about at random at about 10⁶ m s⁻¹, colliding with the atoms. Their average velocity is zero, so there is no current.
- 2With a field, each electron feels a force eE, opposite to E. Its acceleration is a = eE/m.
- 3Between two collisions it gains extra velocity against the field. Each collision throws away this gain and randomises its direction again.
- 4Let τ be the average time between collisions. The average extra velocity is then aτ.
- 5★So, the drift velocity is v_d = eEτ/m, opposite to E. It is only about 10⁻⁴ m s⁻¹.
- 6The energy the electrons hand over in collisions makes the atoms vibrate more, so the wire heats up.
★ key step
Derivation: current I = nAev_d
Take a wire of area of cross-section A with n free electrons per unit volume, all drifting with speed v_d.
- 1In a time Δt, each electron moves a distance v_d Δt along the wire.
- 2So every electron within a length v_d Δt of the area A crosses it in that time. The volume of this slice is A v_d Δt.
- 3Number of electrons crossing = n A v_d Δt. Charge crossing = e n A v_d Δt.
- 4Current = charge ÷ time: I = e n A v_d Δt ÷ Δt.
- 5★So, I = nAev_d: the current is proportional to the drift velocity.
★ key step
Derivation: Ohm's law from the drift of electrons
- 1Put v_d = eEτ/m into I = nAev_d: I = nAe(eEτ/m) = (ne²τA/m)E.
- 2For a wire of length l with a potential difference V across it, E = V/l.
- 3So I = (ne²τA/m)(V/l), which gives V/I = ml/(ne²τA).
- 4★For a given wire at a fixed temperature, n, τ, m, l and A are all constant, so V/I is constant. This is Ohm's law, with R = ml/(ne²τA).
- 5Compare with R = ρl/A: the resistivity is ρ = m/(ne²τ), and the conductivity is σ = 1/ρ = ne²τ/m.
★ key step
How to draw the drift diagram
- Draw a cylinder for the wire. Shade a slice of length v_d Δt next to one cross-section, and label its area A.
- Draw a long arrow along the wire and label it E. Draw the current arrow I in the same direction.
- Draw a short arrow the other way and label it v_d (electrons).
- To show random motion, draw the zigzag path of one electron that slowly shifts opposite to E.
Worked example: drift speed in a copper wire
A copper wire of area of cross-section 2.0 mm² carries a current of 3.4 A. Copper has 8.5 × 10²⁸ free electrons per m³. Find the drift speed of the electrons. How long does an electron take to drift 1 m? (e = 1.6 × 10⁻¹⁹ C)
- Given: I = 3.4 A, A = 2.0 mm² = 2.0 × 10⁻⁶ m², n = 8.5 × 10²⁸ m⁻³.
- Formula: I = nAev_d, so v_d = I/(nAe).
- neA = 8.5 × 10²⁸ × 1.6 × 10⁻¹⁹ × 2.0 × 10⁻⁶ = 27.2 × 10³ = 2.72 × 10⁴ C m⁻¹.
- v_d = 3.4 A ÷ (2.72 × 10⁴ C m⁻¹) = 1.25 × 10⁻⁴ m s⁻¹.
- Time to drift 1 m: t = 1 m ÷ (1.25 × 10⁻⁴ m s⁻¹) = 8.0 × 10³ s, a little over 2 hours.
v_d = 1.25 × 10⁻⁴ m s⁻¹, about 1.3 × 10⁻⁴ m s⁻¹ (0.13 mm per second); about 8.0 × 10³ s to drift 1 m
A ceiling fan starts the moment you press the switch, even though electrons drift less than a millimetre per second. The electric field travels along the wiring almost at the speed of light and sets all the free electrons moving together.
1 marks: “What is the SI unit of electric current?” The ampere (A): 1 A = 1 C s⁻¹.
2 marks: “2.5 × 10¹⁸ electrons pass through a cross-section of a wire in 2 s. Find the current. (e = 1.6 × 10⁻¹⁹ C)” q = Ne = 2.5 × 10¹⁸ × 1.6 × 10⁻¹⁹ = 0.40 C. I = q/t = 0.40 ÷ 2 = 0.20 A, flowing opposite to the electrons.
3 marks: “Define drift velocity. Derive the relation between the current in a wire and the drift velocity of its electrons.” Drift velocity is the average velocity with which free electrons move against the field. In time Δt, the electrons within a length v_dΔt cross area A: their number is nAv_dΔt and their charge nAev_dΔt. So I = nAev_d.
I = nAev_d, read as 'nave' with A: number density, Area, electron charge, drift velocity. Slow drift, fast signal.