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Unit VI · Evolution
11 min readConcept sheet1-mark MCQ or assertion-reason, a 2 or 3-mark question with a short calculation, and a 3-mark question on the factors that disturb equilibrium; also a NEET favourite

Hardy-Weinberg principle

Allele frequencies stay constant from generation to generation unless something disturbs them: p² + 2pq + q² = 1. Any change from this means evolution.

Equationp² + 2pq + q² = 1, the expansion of (p + q)², where p = frequency of allele A, q = frequency of allele a, and p + q = 1
Genotype frequenciesAA = p², Aa = 2pq, aa = q²
Gene poolAll the genes and their alleles in a population
Five disturbing factorsGene flow, genetic drift, mutation, genetic recombination, natural selection

The principle

In a population, each allele of a gene has a frequency (its share of all alleles of that gene). The Hardy-Weinberg principle says that these allele frequencies are stable and constant from generation to generation, so the gene pool stays the same. This state is called genetic equilibrium (Hardy-Weinberg equilibrium). The sum of all allele frequencies is 1. If measured frequencies differ from the expected ones, the direction of the difference shows the extent of evolutionary change.

Where p² + 2pq + q² = 1 comes from

  1. 1
    Take one gene with two alleles, A and a. Let p = frequency of A and q = frequency of a, so p + q = 1.
  2. 2
    With random mating, a gamete carries A with chance p and a with chance q.
  3. 3
    Chance of AA = p × p = p²; chance of aa = q × q = q².
  4. 4
    Aa can form two ways (A from father and a from mother, or the reverse), so its chance = 2pq.
  5. 5★
    All genotypes together: (p + q)² = p² + 2pq + q² = 1.

★ key step

Worked example: from allele frequency to genotypes

Problem

In a population, the frequency of the recessive allele a is 0.3. Find the frequency of the dominant allele and of the genotypes AA, Aa and aa, assuming equilibrium.

Working
  1. Given: q = 0.3.
  2. Rule: p + q = 1, so p = 1 − 0.3 = 0.7.
  3. AA = p² = 0.7 × 0.7 = 0.49.
  4. Aa = 2pq = 2 × 0.7 × 0.3 = 0.42.
  5. aa = q² = 0.3 × 0.3 = 0.09.
  6. Check: 0.49 + 0.42 + 0.09 = 1.00.
Answer

p = 0.7; AA = 0.49, Aa = 0.42, aa = 0.09

Worked example: finding carriers

Problem

In a population of 1000 people, 160 show a recessive trait (aa). Assuming Hardy-Weinberg equilibrium, how many people are heterozygous carriers (Aa)?

Working
  1. Frequency of aa: q² = 160 ÷ 1000 = 0.16.
  2. q = √0.16 = 0.4.
  3. p = 1 − 0.4 = 0.6.
  4. Frequency of Aa = 2pq = 2 × 0.6 × 0.4 = 0.48.
  5. Number of carriers = 0.48 × 1000 = 480.
  6. Check: AA = 0.36 × 1000 = 360; 360 + 480 + 160 = 1000.
Answer

480 heterozygous carriers

The five factors that disturb the equilibrium

FactorHow it changes allele frequencies
Gene migration or gene flowAlleles are added to one population and lost from another when individuals move, again and again
Genetic driftFrequencies change by chance; the founder effect is an extreme case
MutationNew alleles appear
Genetic recombinationNew combinations form during gametogenesis
Natural selectionVariants that survive and reproduce better pass on more of their alleles
In real life

Health workers use this equation to estimate how many people silently carry an allele for a disorder such as thalassemia, which is common in some Indian communities. That helps plan carrier screening before marriage or pregnancy.

Exam angle

2 marks: “State the Hardy-Weinberg principle. What does p² + 2pq + q² = 1 represent?” Allele frequencies in a population stay constant from generation to generation (genetic equilibrium). p² = AA, 2pq = Aa, q² = aa frequencies; it is the expansion of (p + q)².

3 marks: “List the five factors that affect Hardy-Weinberg equilibrium. Explain any two.” Gene flow, genetic drift, mutation, recombination, natural selection. E.g. gene flow adds and removes alleles through repeated migration; genetic drift changes frequencies by chance, as in the founder effect.

2 marks: “In a population, 4% of individuals show a recessive trait. Find the frequency of the dominant allele.” q² = 0.04, so q = 0.2; p = 1 − 0.2 = 0.8.

Remember it

p + q = 1; square it for genotypes. Five things break the balance: My Good Dog Rarely Sleeps (Mutation, Gene flow, Drift, Recombination, Selection).