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Unit X · Vectors
8 min readConcept sheet1-mark MCQ or assertion-reason; a 2-mark question on magnitude or position vector

Scalars, vectors and position vectors

A scalar has only magnitude; a vector has magnitude and direction. The position vector of P(x, y, z) is OP⃗ = xî + yĵ + zk̂.

ScalarA quantity with magnitude only, e.g. mass, time, distance, speed, temperature, work
VectorA quantity with magnitude and direction, e.g. displacement, velocity, force; drawn as a directed line segment AB⃗
Position vector of P(x, y, z)OP⃗ = r⃗ = xî + yĵ + zk̂, with |OP⃗| = √(x² + y² + z²)
Negative of a vectorBA⃗ = −AB⃗: same magnitude, opposite direction

Scalars and vectors

A scalar is a quantity fixed by one real number, its magnitude, such as 10 kg or 5 seconds. A vector needs a magnitude and a direction, such as 30 km/h towards the north. We draw a vector as a directed line segment AB⃗. A is the initial point and B is the terminal point. The length of the segment is the magnitude, written |AB⃗| or |a⃗|. It is never negative. The arrow from A to B shows the direction.

Scalar or vector?

QuantityTypeWhy
Mass of a bag of rice, 10 kgScalarNo direction
Velocity of a train, 80 km/h towards DelhiVectorSpeed with a direction
Temperature in Chennai, 34 °CScalarNo direction
Force of 20 N pulling a cart eastVectorSize and direction
Distance walked, 5 kmScalarPath length only
Displacement, 3 km north-east of homeVectorStraight-line change with a direction
Work done, 50 JScalarWork has no direction, though force and displacement do

Position vector of a point

Fix the origin O(0, 0, 0). For any point P(x, y, z), the vector OP⃗ is the position vector of P, often written r⃗. Using î, ĵ, k̂ (vectors of length 1 along the x, y and z axes), OP⃗ = xî + yĵ + zk̂. By Pythagoras' theorem used twice, its magnitude is |OP⃗| = √(x² + y² + z²), the distance of P from O.

AB⃗ vs BA⃗

AB⃗Starts at A, ends at B. Magnitude = length AB.
BA⃗ = −AB⃗Starts at B, ends at A. Same magnitude, opposite direction. It is the negative of AB⃗.

|−a⃗| = |a⃗| always. Only the direction flips.

Example 1: position vector and its length

Problem

Find the position vector of P(2, −3, 6) and its magnitude.

Working
  1. Position vector: OP⃗ = xî + yĵ + zk̂.
  2. OP⃗ = 2î − 3ĵ + 6k̂
  3. |OP⃗| = √(2² + (−3)² + 6²) = √(4 + 9 + 36)
  4. = √49 = 7
Answer

OP⃗ = 2î − 3ĵ + 6k̂ and |OP⃗| = 7 units.

Example 2: a drone flight

Problem

A drone takes off from a point O on the ground and reaches P(4, 4, 7), in metres. How far is it from O? Write the vector that brings it straight back to O.

Working
  1. OP⃗ = 4î + 4ĵ + 7k̂
  2. |OP⃗| = √(16 + 16 + 49) = √81 = 9 m
  3. The return trip goes from P to O, so it is PO⃗ = −OP⃗.
  4. PO⃗ = −4î − 4ĵ − 7k̂, which also has magnitude 9 m.
Answer

The drone is 9 m from O. Return vector PO⃗ = −4î − 4ĵ − 7k̂.

In real life

A weather report saying 'wind at 20 km/h from the south-west' describes a vector. 'Temperature 34 °C' is a scalar, because it has no direction.

Exam angle

1 marks: “Classify as scalar or vector: (i) 10 J of work, (ii) a 5 N force acting downwards.” (i) Scalar: work has magnitude only. (ii) Vector: the force has a magnitude and a direction.

1 marks: “If |a⃗| = 4, what is |−a⃗|?” 4. The negative of a vector has the same magnitude and the opposite direction.

2 marks: “Find the distance of P(−2, 3, 6) from the origin and write the vector PO⃗.” OP⃗ = −2î + 3ĵ + 6k̂, |OP⃗| = √(4 + 9 + 36) = 7. PO⃗ = −OP⃗ = 2î − 3ĵ − 6k̂.

Remember it

Scalar: how much. Vector: how much and which way.