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Unit III · Matrices
8 min readConcept sheet1-mark MCQ; 2 or 3-mark 'find the matrix X' questions

Addition, subtraction and scalar multiplication

Add or subtract matrices of the same order entry by entry. To multiply by a scalar k, multiply every entry by k: kA = [k aᵢⱼ].

SumA + B = [aᵢⱼ + bᵢⱼ], defined only when A and B have the same order
Scalar multiplekA = [k aᵢⱼ]. The negative of A is −A = (−1)A.
DifferenceA − B = A + (−1)B = [aᵢⱼ − bᵢⱼ]
Key propertiesA + B = B + A; (A + B) + C = A + (B + C); k(A + B) = kA + kB; (k + l)A = kA + lA

Adding, subtracting and scaling

Matrices of the same order are added by adding the entries in the same positions: if A = [aᵢⱼ] and B = [bᵢⱼ] are both m × n, then A + B = [aᵢⱼ + bᵢⱼ], also m × n. Subtraction works the same way. Matrices of different orders cannot be added. A scalar is just a number. To find kA, multiply every entry of A by k. (Matrices are written row by row here, with rows separated by semicolons.)

Example 1: a combination

Problem

If A = [2, −1; 3, 0] and B = [1, 4; −2, 5], find 3A − 2B.

Working
  1. Rule: kA = [k aᵢⱼ], and subtract entry by entry.
  2. 3A = [6, −3; 9, 0]
  3. 2B = [2, 8; −4, 10]
  4. 3A − 2B = [6 − 2, −3 − 8; 9 − (−4), 0 − 10]
Answer

3A − 2B = [4, −11; 13, −10]

Properties (A, B, C of the same order; k and l scalars)

PropertyStatement
Commutative law of additionA + B = B + A
Associative law of addition(A + B) + C = A + (B + C)
Additive identityA + O = O + A = A, where O is the zero matrix of the same order
Additive inverseA + (−A) = (−A) + A = O
Scalar times a sum of matricesk(A + B) = kA + kB
Sum of scalars times a matrix(k + l)A = kA + lA

Example 2: two unknown matrices (board style)

Problem

Find X and Y if X + Y = [7, 3; 2, 9] and X − Y = [1, 5; 4, −1].

Working
  1. Rule: matrix equations of the same order can be added and subtracted like ordinary equations.
  2. Add the two equations: 2X = [8, 8; 6, 8].
  3. So X = [4, 4; 3, 4].
  4. Subtract the second from the first: 2Y = [6, −2; −2, 10].
  5. So Y = [3, −1; −1, 5].
  6. Check: X + Y = [7, 3; 2, 9] and X − Y = [1, 5; 4, −1].
Answer

X = [4, 4; 3, 4], Y = [3, −1; −1, 5]

Example 3: solve for X

Problem

Find X if 2A + 3X = B, where A = [1, 2; 0, −3] and B = [8, 1; 9, −6].

Working
  1. Rule: rearrange as with numbers: 3X = B − 2A.
  2. 2A = [2, 4; 0, −6]
  3. B − 2A = [8 − 2, 1 − 4; 9 − 0, −6 − (−6)] = [6, −3; 9, 0]
  4. X = (1/3)[6, −3; 9, 0] = [2, −1; 3, 0]
Answer

X = [2, −1; 3, 0]

In real life

A ration shop's stock matrix of rice, wheat and sugar plus the matrix of new deliveries gives the new stock by matrix addition. A 10% price rise on every item is scalar multiplication by 1.1.

Exam angle

1 marks: “If A + B = O, where O is the zero matrix, what is B?” B = −A, the additive inverse of A.

3 marks: “Find X and Y if 2X + Y = [4, 5; 3, 2] and X − Y = [−1, 1; −3, 1].” Add the equations: 3X = [3, 6; 0, 3], so X = [1, 2; 0, 1]. Then Y = X − [−1, 1; −3, 1] = [2, 1; 3, 0]. Check: 2X + Y = [4, 5; 3, 2].

Remember it

Same order to add; a scalar hits every entry.