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Unit V · Continuity and differentiability
10 min readConcept sheet1-mark MCQ; 2-mark questions; used inside most 3 and 5-mark derivative questions

Exponential and logarithmic functions and their derivatives

y = eˣ and y = log x are inverse functions. Their derivatives are simple: d/dx eˣ = eˣ and d/dx log x = 1/x for x > 0.

The number ee ≈ 2.718, an irrational number. In this chapter log x means the natural log, logₑ x
Inverse pairy = eˣ exactly when x = log y; log(eˣ) = x for every real x, and e^(log x) = x for x > 0
Derivativesd/dx eˣ = eˣ; d/dx log x = 1/x (x > 0); d/dx aˣ = aˣ log a (a > 0)
Log lawslog(mn) = log m + log n; log(m/n) = log m − log n; log(mⁿ) = n log m

The two functions

An exponential function is y = bˣ with base b > 1. Its domain is all real numbers, its range is y > 0, and it passes through (0, 1). The most important base is e ≈ 2.718. The logarithmic function y = log_b x is its inverse: log_b x = y exactly when bʸ = x. Its domain is x > 0, so the log of 0 or of a negative number is not defined. Here log x means logₑ x, the natural logarithm. We write a^(b) for a raised to the power b when the power is long.

eˣ and log x side by side

Propertyy = eˣy = log x
DomainAll real numbersx > 0
Rangey > 0All real numbers
Passes through(0, 1)(1, 0)
ShapeAlways increasing; hugs the negative x-axisAlways increasing; hugs the negative y-axis near x = 0
Derivativeeˣ1/x

How to draw the graphs of y = eˣ and y = log x

  • Draw the x and y axes, and the line y = x as a dashed line.
  • For y = eˣ, plot (−1, 1/e), (0, 1) and (1, e), with e ≈ 2.7. Draw a rising curve that comes closer and closer to the negative x-axis but never meets it.
  • For y = log x, plot (1/e, −1), (1, 0) and (e, 1). Draw a rising curve that runs down along the negative y-axis, close to it but never meeting it.
  • The two curves are mirror images in the line y = x. Label each curve and the points (0, 1) and (1, 0).

Derivatives with the chain rule

FunctionDerivative
eˣeˣ
e^(f(x))e^(f(x)) × f′(x)
log x, x > 01/x
log f(x), f(x) > 0f′(x)/f(x)
aˣ, a > 0aˣ log a

Example 1: direct use

Problem

Differentiate (i) e^(x²), (ii) log(sin x), 0 < x < π, (iii) 5ˣ.

Working
  1. (i) Chain rule: d/dx e^(x²) = e^(x²) × 2x = 2x e^(x²)
  2. (ii) d/dx log(sin x) = (1/sin x) × cos x = cot x
  3. (iii) d/dx 5ˣ = 5ˣ log 5
Answer

(i) 2x e^(x²); (ii) cot x; (iii) 5ˣ log 5

Example 2: board style

Problem

Differentiate y = log(x + √(x² + 1)).

Working
  1. Let u = x + √(x² + 1). Then dy/dx = (1/u) × du/dx.
  2. du/dx = 1 + 2x/(2√(x² + 1)) = 1 + x/√(x² + 1)
  3. = (√(x² + 1) + x)/√(x² + 1)
  4. dy/dx = [1/(x + √(x² + 1))] × [(x + √(x² + 1))/√(x² + 1)]
  5. The factor x + √(x² + 1) cancels.
Answer

dy/dx = 1/√(x² + 1)

In real life

Bacteria in idli batter and curd multiply roughly exponentially while they ferment. Sound levels in decibels and pH in chemistry use logarithms to squeeze huge ranges into small numbers.

Exam angle

1 marks: “Find d/dx (e^(2x + 3)).” Chain rule: e^(2x + 3) × 2 = 2e^(2x + 3).

2 marks: “Differentiate y = e^(tan x) + log(sec x), 0 < x < π/2.” dy/dx = sec²x e^(tan x) + (sec x tan x)/sec x = sec²x e^(tan x) + tan x.

2 marks: “Differentiate y = sin(log x), x > 0.” dy/dx = cos(log x) × (1/x) = cos(log x)/x.

Remember it

eˣ stays eˣ; log x becomes 1/x.