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Unit XI · Areas related to circles
6 min readConcept sheet1-mark MCQ; mostly used inside sector, segment and shaded-region questions

Circumference and area of a circle (review)

For a circle of radius r, the circumference is 2πr and the area is πr². π is about 22/7 or 3.14; use the value the question gives.

CircumferenceC = 2πr = πd
AreaA = πr²
π22/7 or 3.14 (an irrational number, about 3.1416)
WheelsOne revolution moves the wheel forward by one circumference

Formulas for circles

FigurePerimeterArea
Circle of radius r2πrπr²
Semicircleπr + 2r (curved edge + diameter)πr²/2
Quadrant (quarter circle)πr/2 + 2rπr²/4
Ring between radii R and r2πR + 2πr (both edges)π(R² − r²)

Choosing π and units

Your textbook now starts this chapter directly with sectors and segments. So you will mostly use these formulas inside those questions, for example to find r from a given circumference. Use π = 22/7 when the radius or diameter is a multiple of 7. Use π = 3.14 when the question says so. If no value is given, use 22/7 and write that you did. A length (circumference, perimeter) is in cm or m. An area is in cm² or m². Round decimal answers to 2 decimal places unless told otherwise.

Circumference and area

Problem

Find the circumference and the area of a circle of radius 21 cm. (Use π = 22/7)

Working
  1. Circumference = 2πr = 2 × (22/7) × 21.
  2. = 2 × 22 × 3 = 132 cm.
  3. Area = πr² = (22/7) × 21 × 21.
  4. = 22 × 3 × 21 = 1386 cm².
Answer

Circumference = 132 cm, area = 1386 cm²

Word problem: bicycle wheel

Problem

A bicycle wheel has diameter 70 cm. How many complete revolutions does it make to travel 1.1 km? (Use π = 22/7)

Working
  1. Distance in one revolution = circumference = πd = (22/7) × 70 = 220 cm.
  2. 1.1 km = 1100 m = 110000 cm.
  3. Number of revolutions = 110000 ÷ 220 = 500.
Answer

500 revolutions

Word problem: a path round a park

Problem

A circular park has radius 35 m. A path 7 m wide runs all around it, outside. Find the area of the path. (Use π = 22/7)

Working
  1. Inner radius r = 35 m; outer radius R = 35 + 7 = 42 m.
  2. Area of the ring = π(R² − r²).
  3. R² − r² = 1764 − 1225 = 539.
  4. Area = (22/7) × 539 = 22 × 77 = 1694 m².
Answer

1694 m²

In real life

A roti of radius 14 cm covers (22/7) × 196 = 616 cm² of the tawa. An auto-rickshaw meter finds distance from wheel turns: distance = turns × circumference.

Exam angle

1 marks: “Find the area of a circle whose circumference is 44 cm. (Use π = 22/7)” 2πr = 44 gives r = 7 cm. Area = (22/7) × 49 = 154 cm².

2 marks: “The radii of two circles are 15 cm and 13 cm. Find the radius of the circle whose circumference is the sum of their circumferences.” 2πR = 2π(15) + 2π(13), so R = 15 + 13 = 28 cm.

3 marks: “A wheel has diameter 56 cm. How many revolutions will it make to cover 352 m? (Use π = 22/7)” Circumference = (22/7) × 56 = 176 cm. 352 m = 35200 cm. Revolutions = 35200 ÷ 176 = 200.

Remember it

Circumference wraps around (2πr, in cm). Area fills inside (πr², in cm²).