Line of sight, angle of elevation and angle of depression
The line of sight joins your eye to the object. Looking up, it makes an angle of elevation with the horizontal; looking down, an angle of depression.
Angle of elevation vs angle of depression
Both angles are always measured from the horizontal line through the eye, never from the vertical.
Why the two angles are equal
Suppose you stand on a cliff top A and see a boat B below. Draw a horizontal line through A. The sea level through B is also horizontal, so the two lines are parallel. The line of sight AB cuts both lines. So the angle of depression at A equals the angle of elevation at B, as alternate interior angles. In your figure, always mark this angle inside the triangle at B. It saves many mistakes.
How to draw a heights and distances figure
- 1Draw the ground as a horizontal line.
- 2Draw the tower, tree or building as a vertical line from the ground. Mark the right angle at its foot.
- 3Mark the observer's point on the ground, or at the top of a building.
- 4Join the eye to the object. This is the line of sight.
- 5★For a depression, draw a dotted horizontal line through the eye and mark the angle below it. Then mark the equal angle inside the triangle.
- 6Write the given angle and lengths. Call the unknown h or x. If the observer's eye height is given, draw a horizontal line at eye level.
★ key step
Using the equal angles
A boy on the roof of a 12 m tall building sees a car on the road at an angle of depression of 30°. Find the angle of elevation of the boy from the car, and the distance of the car from the building. (Use √3 = 1.732)
- Let AB = 12 m be the building and C the car. ∠B = 90°.
- Angle of elevation of A from C = angle of depression = 30° (alternate angles).
- In ΔABC, tan 30° = AB/BC.
- 1/√3 = 12/BC, so BC = 12√3 m.
- BC = 12 × 1.732 = 20.784 m ≈ 20.78 m.
Angle of elevation = 30°; the car is about 20.78 m from the building.
Adding the observer's height
A girl whose eyes are 1.4 m above the ground stands 25 m from a tree. The angle of elevation of the top of the tree from her eyes is 45°. Find the height of the tree.
- Draw a horizontal line from her eyes E to the tree, meeting it at D. ED = 25 m.
- Let T be the top of the tree. In ΔEDT, tan 45° = TD/ED.
- 1 = TD/25, so TD = 25 m.
- D is 1.4 m above the ground, the same as her eyes.
- Height of the tree = TD + 1.4 = 25 + 1.4 = 26.4 m.
26.4 m
Coast guard staff at a lighthouse in Kanyakumari judge how far a ship is from its angle of depression. Builders find the height of a temple gopuram from an angle of elevation, without climbing it.
1 marks: “The angle of depression of a car from the top of a tower is 45°. What is the angle of elevation of the top of the tower from the car?” 45°, because the two angles are alternate interior angles between parallel horizontal lines.
2 marks: “From a point 40 m from the foot of a tower on level ground, the angle of elevation of its top is 60°. Find the height of the tower. (Use √3 = 1.732)” tan 60° = h/40, so h = 40√3 = 40 × 1.732 = 69.28 m.
3 marks: “A man whose eyes are 1.6 m above the ground stands 18 m from a pole. The angle of elevation of the top of the pole from his eyes is 30°. Find the height of the pole. (Use √3 = 1.732)” Height above eye level = 18 tan 30° = 18/√3 = 6√3 = 10.392 m. Pole = 10.392 + 1.6 = 11.992 ≈ 11.99 m.
Elevation: eyes up. Depression: eyes down. Both start from the horizontal.