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Unit XIV · Probability
9 min readConcept sheet1-mark MCQ; a 3-mark question on two dice

Throwing dice: one die and two dice

One die has 6 outcomes. Two dice have 6 × 6 = 36 ordered pairs, like (2, 5). Use the 36-outcome grid to count sums and doublets.

One die6 outcomes: 1, 2, 3, 4, 5, 6
Two dice36 outcomes: (1, 1) to (6, 6)
DoubletThe same number on both dice: 6 outcomes, P = 1/6
Most likely sum7, with 6 outcomes: P = 1/6

One die

A die (plural dice) is a cube with faces numbered 1 to 6. A fair die shows each face with the same chance, so P(any one number) = 1/6. The prime numbers on a die are 2, 3 and 5. The even numbers are 2, 4 and 6. With two dice, an outcome is a pair: (2, 5) means 2 on the first die and 5 on the second.

Two dice: outcomes for each sum

SumOutcomes (first die, second die)CountProbability
2(1, 1)11/36
3(1, 2), (2, 1)22/36 = 1/18
4(1, 3), (2, 2), (3, 1)33/36 = 1/12
5(1, 4), (2, 3), (3, 2), (4, 1)44/36 = 1/9
6(1, 5), (2, 4), (3, 3), (4, 2), (5, 1)55/36
7(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)66/36 = 1/6
8(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)55/36
9(3, 6), (4, 5), (5, 4), (6, 3)44/36 = 1/9
10(4, 6), (5, 5), (6, 4)33/36 = 1/12
11(5, 6), (6, 5)22/36 = 1/18
12(6, 6)11/36

Worked example 1: one die

Problem

A die is thrown once. Find the probability of getting (i) a prime number, (ii) a number less than 3.

Working
  1. Formula: P(E) = favourable outcomes ÷ total outcomes. Total = 6.
  2. Primes: 2, 3, 5 (3 outcomes). P(prime) = 3/6 = 1/2.
  3. Less than 3: 1, 2 (2 outcomes). P = 2/6 = 1/3.
Answer

P(prime) = 1/2; P(less than 3) = 1/3.

Worked example 2: two dice in a board game

Problem

In a board game, two dice are thrown together. Find the probability that (i) the sum is 9, (ii) a doublet appears (the same number on both dice).

Working
  1. Formula: P(E) = favourable outcomes ÷ total outcomes.
  2. Total outcomes = 6 × 6 = 36.
  3. Sum 9: (3, 6), (4, 5), (5, 4), (6, 3). That is 4 outcomes, so P(sum 9) = 4/36 = 1/9.
  4. Doublets: (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6). That is 6 outcomes.
  5. P(doublet) = 6/36 = 1/6.
Answer

P(sum 9) = 1/9; P(doublet) = 1/6.

How to draw the 36-outcome grid

  • Draw a 6 × 6 table.
  • Label the rows 1 to 6 for the first die and the columns 1 to 6 for the second die.
  • In each cell, write the pair, for example (2, 5), or its sum, 7.
  • The cells on the diagonal from top left to bottom right are the doublets.
  • Each slanting line from top right to bottom left has the same sum. Count its cells to get the favourable outcomes.
In real life

Games like Ludo and Snakes and Ladders depend on a fair die. With two dice, a sum of 7 comes up most often, so players can expect it more than 2 or 12.

Exam angle

1 marks: “A die is thrown once. Find the probability of getting a number that is not a multiple of 3.” Multiples of 3 are 3 and 6. The others are 1, 2, 4, 5 (4). P = 4/6 = 2/3.

3 marks: “Two dice are thrown together. Find the probability that (i) the sum is 8, (ii) the product is 6, (iii) the sum is more than 10.” 36 outcomes. (i) Sum 8: (2, 6), (3, 5), (4, 4), (5, 3), (6, 2), so 5/36. (ii) Product 6: (1, 6), (6, 1), (2, 3), (3, 2), so 4/36 = 1/9. (iii) Sum 11 or 12: (5, 6), (6, 5), (6, 6), so 3/36 = 1/12.

Remember it

Two dice: 36 pairs. Sum 7 is the peak with 6 ways; doublets also have 6 ways.