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Unit I · Relations and functions
7 min readConcept sheetPart I (1 mark) to match a function with its graph; Part II (2 marks); a real-life linear function can be Part III (5 marks)

Special functions and their graphs

Know the shapes: identity and linear give straight lines, constant a flat line, modulus a V, quadratic a parabola, cubic an S-curve and reciprocal a hyperbola.

Identityf(x) = x; graph is the line y = x through the origin
Constantf(x) = c; the range has one element; graph is a horizontal line
Linear and quadraticf(x) = mx + c, m ≠ 0; f(x) = ax² + bx + c, a ≠ 0
Cubic and reciprocalf(x) = ax³ + bx² + cx + d, a ≠ 0; f(x) = 1/x, x ≠ 0

The special functions

FunctionRuleShape of the graphExample
Identityf(x) = xStraight line through the origin, making 45° with the x-axisf(5) = 5
Constantf(x) = cHorizontal line y = c; range = {c}f(x) = 4 for every x
Linearf(x) = mx + c, m ≠ 0Straight line that is not horizontal or verticalf(x) = 2x + 1
Modulus (absolute value)f(x) = |x|: x when x ≥ 0, and −x when x < 0V shape with its corner at the origin; never below the x-axis, so the range is [0, ∞)f(−3) = |−3| = 3
Quadraticf(x) = ax² + bx + c, a ≠ 0Parabola; opens upward if a > 0, downward if a < 0f(x) = x² − 4
Cubicf(x) = ax³ + bx² + cx + d, a ≠ 0A curve like a stretched S; y = x³ runs from the third quadrant to the firstf(x) = x³
Reciprocalf(x) = 1/x, x ≠ 0Two curved branches in the first and third quadrants (a rectangular hyperbola); never meets the axesf(2) = 1/2

Two more words from your textbook

A function f: A → B is a real valued function when its range is a subset of R, the set of real numbers. Every function in the table is real valued. The modulus function is not linear. Its graph is made of two straight pieces: y = x for x ≥ 0 and y = −x for x < 0.

How to draw the graph of y = x²

  1. 1
    Make a table for x = −3, −2, −1, 0, 1, 2, 3. The y values are 9, 4, 1, 0, 1, 4, 9.
  2. 2
    Draw the axes on graph paper. Take 1 cm = 1 unit on both axes and write the scale.
  3. 3
    Plot (−3, 9), (−2, 4), (−1, 1), (0, 0), (1, 1), (2, 4) and (3, 9).
  4. 4
    Join the points with a smooth U-shaped curve, freehand, not with a ruler. Label it y = x².
  5. 5
    Note the shape: it is symmetric about the y-axis, and its lowest point (the vertex) is the origin.

Example 1: recognise the function

Problem

Name the type of each function: (i) f(x) = 7 (ii) g(x) = 3 − 2x (iii) h(x) = 2x² − x + 5 (iv) p(x) = x³ − 1 (v) q(x) = 1/x, x ≠ 0.

Working
  1. (i) The output is always 7, so f is a constant function.
  2. (ii) The highest power of x is 1, so g is a linear function.
  3. (iii) The highest power of x is 2, so h is a quadratic function.
  4. (iv) The highest power of x is 3, so p is a cubic function.
  5. (v) x is in the denominator, so q is the reciprocal function.
Answer

Constant, linear, quadratic, cubic and reciprocal.

Example 2: a linear function in real life

Problem

A cab charges a fixed ₹ 50 plus ₹ 12 per km (example rates). Write the fare as a function of the distance x km. Find the fare for 15 km, and the distance travelled when the fare is ₹ 290.

Working
  1. Fare f(x) = 12x + 50. It has the form mx + c with m = 12 ≠ 0, so it is linear.
  2. f(15) = 12 × 15 + 50 = 180 + 50 = 230.
  3. 12x + 50 = 290 ⇒ 12x = 240 ⇒ x = 20.
  4. Check: f(20) = 240 + 50 = 290.
Answer

f(x) = 12x + 50; the fare for 15 km is ₹ 230; ₹ 290 pays for 20 km.

In real life

Buying paneer at an example rate of ₹ 400 per kg gives a linear function: cost = 400 × weight. A fixed monthly fee that does not change with use is a constant function.

Exam angle

1 marks: “The graph of f(x) = 1/x is: (1) a straight line (2) a parabola (3) a rectangular hyperbola (4) a circle.” (3) a rectangular hyperbola.

2 marks: “f: R → R is defined by f(x) = 3x − 2. Name the type of function and find f(4) − f(1).” Linear, because it has the form mx + c with m = 3 ≠ 0. f(4) − f(1) = 10 − 1 = 9.

5 marks: “A tank holds 500 litres of water and drains at 20 litres per minute. (i) Write the volume V(t) left after t minutes. (ii) Name the type of function. (iii) Find V(10). (iv) When is the tank empty?” V(t) = 500 − 20t, a linear function. V(10) = 500 − 200 = 300 litres. 500 − 20t = 0 gives t = 25 minutes, so the domain is 0 ≤ t ≤ 25.

Remember it

The highest power tells the shape: power 0 flat, 1 straight, 2 parabola, 3 S-curve; x in the denominator gives a hyperbola.