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Unit IV · Geometry
9 min readConcept sheetPart I MCQ, Part II (2 marks), and Part III shadow or area problems (5 marks)

Similar triangles: criteria and properties

Similar triangles have the same shape: equal angles and proportional sides. Test with AA, SAS or SSS. Area ratio = (side ratio)².

Similar (~)Corresponding angles equal and corresponding sides in the same ratio
CriteriaAA, SAS (included angle equal, sides in ratio), SSS (all sides in ratio)
Perimeters, altitudes, mediansIn the same ratio as the corresponding sides
Areasar(ΔABC)/ar(ΔPQR) = AB²/PQ², the square of the side ratio

The three similarity criteria

CriterionWhat you must showExample
AATwo angles of one triangle equal two angles of the other. The third angles are then equal too.∠A = ∠P and ∠B = ∠Q, so ΔABC ~ ΔPQR
SASOne pair of angles equal, and the sides that include these angles in the same ratio.∠A = ∠P and AB/PQ = AC/PR
SSSAll three pairs of corresponding sides in the same ratio.Sides 3, 4, 5 cm and 6, 8, 10 cm: every ratio is 1/2

Congruent vs similar

Congruent (≅)Same shape and same size. Corresponding sides are equal, so the side ratio is 1.
Similar (~)Same shape, but the size may differ. Corresponding angles are equal. Corresponding sides are proportional (in the same ratio).

All congruent triangles are similar, but similar triangles need not be congruent. Write the letters in matching order: ΔABC ~ ΔPQR means A ↔ P, B ↔ Q and C ↔ R.

Properties of similar triangles

  • If ΔABC ~ ΔPQR, then AB/PQ = BC/QR = CA/RP. This common ratio is the scale factor.
  • The perimeters, altitudes (heights) and medians are in the same ratio as the sides.
  • The areas are in the ratio of the squares of corresponding sides: ar(ΔABC)/ar(ΔPQR) = AB²/PQ².
  • In a right triangle, the perpendicular from the right angle to the hypotenuse makes two triangles. They are similar to each other and to the whole triangle.
  • Two triangles with a common vertex and bases on the same line have areas in the ratio of their bases.

Example 1: height from a shadow (word problem)

Problem

At 4 p.m., a boy 1.6 m tall casts a shadow 2.4 m long. At the same time, the flagpole (kodimaram) of a temple casts a shadow 12 m long. Find the height of the flagpole.

Working
  1. The sun's rays fall at the same angle on both. Both stand at 90° to the ground.
  2. So the two triangles (height, shadow, ray) are similar by AA.
  3. Corresponding sides are proportional: h/1.6 = 12/2.4
  4. h = 1.6 × 12/2.4
  5. h = 1.6 × 5 = 8
Answer

The flagpole is 8 m tall.

Example 2: ratio of areas

Problem

ΔABC ~ ΔPQR. The area of ΔABC is 49 cm² and the area of ΔPQR is 81 cm². If QR = 13.5 cm, find BC.

Working
  1. Area theorem: ar(ΔABC)/ar(ΔPQR) = (BC/QR)²
  2. (BC/QR)² = 49/81
  3. BC/QR = 7/9 (take the positive square root)
  4. BC = (7/9) × 13.5
  5. BC = 7 × 1.5 = 10.5
Answer

BC = 10.5 cm

In real life

A house plan is similar to the real house, drawn to a scale. You can find the height of a temple gopuram or a coconut tree from its shadow, without climbing it.

Exam angle

1 marks: “ΔABC ~ ΔDEF with AB = 3 cm and DE = 6 cm. Find ar(ΔABC) : ar(ΔDEF).” Side ratio is 1 : 2, so the area ratio is 1² : 2² = 1 : 4.

2 marks: “Are the triangles with sides 4 cm, 6 cm, 8 cm and 6 cm, 9 cm, 12 cm similar?” 4/6 = 6/9 = 8/12 = 2/3. All three ratios are equal, so the triangles are similar by SSS.

5 marks: “A boy 1.5 m tall casts a 2 m shadow. At the same time a tower casts a 30 m shadow. Find the height of the tower.” Same sun angle and both vertical, so the triangles are similar by AA. h/1.5 = 30/2, so h = 1.5 × 15 = 22.5 m.

Remember it

AA, SAS, SSS: for similarity, match angles or ratios, not just lengths. Areas go by the square of the side ratio.