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Unit VII · Mensuration
9 min readConcept sheetPart II (2 marks) and often a Part III answer (5 marks)

Combined solids: surface area and volume

For a solid made of two or more shapes, add the volumes of the parts. For surface area, add only the outer surfaces; joined faces are hidden.

Volume ruleAdd the volumes of the parts; subtract any part cut out
Surface area ruleAdd only the outer surfaces; leave out faces where parts join
Capsule (cylinder + two hemispheres)Surface area 2πrh + 4πr²
Toy (cone on a hemisphere)TSA πrl + 2πr²

Rules for combined solids

  • Volume: add the volumes of all the parts. If a part is cut out, subtract its volume.
  • Surface area: add only the surfaces on the outside. Faces where two parts are joined are hidden, so leave them out.
  • If a shape is scooped out, its inner surface is now on the outside, so add it.
  • Write the dimensions of each part on your figure before you start.

Common combined solids

ObjectPartsTotal surface areaVolume
ToyCone on a hemisphere, same rπrl + 2πr²(1/3)πr²h + (2/3)πr³
Medicine capsuleCylinder with a hemisphere at each end2πrh + 4πr²πr²h + (4/3)πr³
TentCylinder with a cone on top2πrh₁ + πrl (no floor)πr²h₁ + (1/3)πr²h₂ (h₁ cylinder, h₂ cone)
Ice cream coneCone filled and topped with a hemisphereπrl + 2πr²(1/3)πr²h + (2/3)πr³

Example 1: a wooden toy

Problem

A wooden toy is a cone fixed on a hemisphere of the same radius, 7 cm. The total height of the toy is 31 cm. Find its total surface area and volume. (Take π = 22/7.)

Working
  1. The height of the hemisphere is its radius, 7 cm. So the cone's height h = 31 − 7 = 24 cm.
  2. Slant height l = √(24² + 7²) = √625 = 25 cm
  3. TSA = CSA of cone + CSA of hemisphere = πrl + 2πr²
  4. = 22/7 × 7 × 25 + 2 × 22/7 × 7 × 7
  5. = 550 + 308 = 858 cm²
  6. Volume = (1/3)πr²h + (2/3)πr³ = (1/3)πr²(h + 2r)
  7. = 1/3 × 22/7 × 7 × 7 × (24 + 14) = 1/3 × 154 × 38
  8. = 5852/3 ≈ 1950.67 cm³
Answer

TSA = 858 cm², volume ≈ 1950.67 cm³

Example 2: a medicine capsule

Problem

A medicine capsule is a cylinder with a hemisphere at each end. It is 14 mm long and its radius is 3.5 mm. Find its surface area and volume. (Take π = 22/7.)

Working
  1. Length of the cylinder part h = 14 − 3.5 − 3.5 = 7 mm.
  2. Surface area = CSA of cylinder + 2 × CSA of hemisphere = 2πrh + 4πr²
  3. = 2 × 22/7 × 3.5 × 7 + 4 × 22/7 × 3.5 × 3.5
  4. = 154 + 154 = 308 mm²
  5. Volume = πr²h + (4/3)πr³
  6. = 22/7 × 3.5 × 3.5 × 7 + 4/3 × 22/7 × 3.5 × 3.5 × 3.5
  7. = 269.5 + 179.67 = 449.17 mm³
Answer

Surface area = 308 mm², volume ≈ 449.17 mm³

How to draw a combined solid

  • Draw each part with the same radius where they join, for example a cone standing on a semicircle.
  • Draw the joining circle as a dotted ellipse, because it is hidden inside.
  • Mark r, the height of each part and any slant height l.
  • Write the total height and show how it splits, for example 31 cm = 24 cm + 7 cm.
In real life

A temple festival tent (cylinder + cone), a medicine capsule (cylinder + two hemispheres) and an ice cream cone (cone + hemisphere) are combined solids.

Exam angle

1 marks: “A solid is a cylinder with a hemisphere at each end. Which surfaces make up its surface area?” The curved surface of the cylinder and the curved surfaces of the two hemispheres: 2πrh + 4πr².

2 marks: “A tent is a cylinder of radius 7 m and height 4 m with a cone of slant height 10 m on top. Find the area of canvas needed. (π = 22/7)” Canvas = 2πrh + πrl = 2 × 22/7 × 7 × 4 + 22/7 × 7 × 10 = 176 + 220. Answer: 396 m².

5 marks: “A solid wooden cylinder has radius 5 cm and height 12 cm. A cone of the same radius and height is carved out from one end. Find the volume and total surface area of the remaining solid. (π = 3.14)” Volume = πr²h − (1/3)πr²h = 942 − 314 = 628 cm³. l = 13 cm. TSA = 2πrh + πr² + πrl = 376.8 + 78.5 + 204.1 = 659.4 cm².

Remember it

Volumes all add up; surfaces count only if you can touch them.