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Unit IV · The d- and f-block elements
11 min readConcept sheet2 and 3-mark "explain the E° value" questions; 1-mark MCQ or assertion-reason on Cr²⁺ and Mn³⁺; also a NEET favourite

Standard electrode potentials and chemical reactivity

E°(M²⁺/M) becomes less negative across the 3d series, and copper's is positive. Stable d⁰, d³, d⁵ and d¹⁰ ions explain the odd values.

What decides E°Enthalpy of atomisation + first and second ionisation enthalpies + hydration enthalpy (a negative term), for M(s) → M²⁺(aq)
E°(M²⁺/M), 3d seriesTi −1.63, V −1.18, Cr −0.90, Mn −1.18, Fe −0.44, Co −0.28, Ni −0.25, Cu +0.34, Zn −0.76 V
E°(M³⁺/M²⁺)Ti −0.37, V −0.26, Cr −0.41, Mn +1.57, Fe +0.77, Co +1.97 V
Key resultsCu does not give H₂ with dilute acids; Cr²⁺ is a strong reducing agent; Mn³⁺ and Co³⁺ are strong oxidising agents

Energy steps for M(s) → M²⁺(aq)

The smaller the net energy needed, the more negative E°(M²⁺/M) and the more easily the metal forms M²⁺ ions.

E°(M²⁺/M) values and what they mean

MetalE° (V)Comment and reason
Ti, V, Cr−1.63, −1.18, −0.90Become less negative: the sum of the first and second ionisation enthalpies generally rises across the series
Mn−1.18More negative than the trend: Mn²⁺ is the stable half-filled d⁵
Fe, Co−0.44, −0.28Continue the general trend
Ni−0.25More negative than expected for its position: Ni²⁺ has the most negative hydration enthalpy
Cu+0.34Only positive value: high enthalpy of atomisation and high ionisation enthalpies are not balanced by its hydration enthalpy
Zn−0.76More negative than expected: Zn²⁺ is the stable full d¹⁰

E°(M³⁺/M²⁺) values and what they mean

CoupleE° (V)Meaning
Cr³⁺/Cr²⁺−0.41Cr²⁺ is easily oxidised to Cr³⁺ (stable d³, half-filled t₂g level): Cr²⁺ is a strong reducing agent
V³⁺/V²⁺−0.26Fairly low, linked to the stability of V²⁺ (half-filled t₂g level)
Mn³⁺/Mn²⁺+1.57Very high: Mn²⁺ (d⁵) is very stable, so Mn³⁺ is a strong oxidising agent
Fe³⁺/Fe²⁺+0.77Comparatively low: Fe³⁺ is also d⁵, so it is quite stable
Co³⁺/Co²⁺+1.97Very high: Co³⁺ is a strong oxidising agent in water
Scvery lowSc³⁺ has the stable noble-gas configuration, so Sc exists almost only as Sc³⁺

Cr²⁺ and Mn³⁺: both d⁴, opposite behaviour

Cr²⁺ is reducingCr²⁺ (d⁴) loses an electron to become Cr³⁺ (d³), which has a stable half-filled t₂g level. So Cr²⁺ is easily oxidised: it is a reducing agent.
Mn³⁺ is oxidisingMn³⁺ (d⁴) gains an electron to become Mn²⁺ (d⁵), a stable half-filled set. So Mn³⁺ is easily reduced: it is an oxidising agent.

Chemical reactivity

Transition metals vary widely in reactivity. Most first series metals, except copper, are fairly electropositive and dissolve in mineral acids. Titanium and vanadium, though, hardly react with dilute non-oxidising acids at room temperature (they are passive), because a thin oxide layer protects them. The E°(M²⁺/M) values show a decreasing tendency to form M²⁺ across the series. Copper cannot give H₂ with dilute non-oxidising acids; it reacts only with oxidising acids such as nitric acid and hot concentrated sulphuric acid. Ti²⁺, V²⁺ and Cr²⁺ are strong reducing agents and give hydrogen with dilute acid: 2Cr²⁺(aq) + 2H⁺(aq) → 2Cr³⁺(aq) + H₂(g).

In real life

Copper pots do not give hydrogen with sour foods like tamarind because E°(Cu²⁺/Cu) is positive, but air can still slowly dissolve copper in acid, so they are tin-coated (kalai). Iron kadais, with a negative E°, add a little iron to food.

Exam angle

2 marks: “Why is E°(Cu²⁺/Cu) positive, unlike the other 3d metals? What does it tell you about copper and dilute HCl?” Copper's high enthalpy of atomisation and ionisation enthalpies are not balanced by the hydration enthalpy of Cu²⁺. So Cu cannot reduce H⁺: it does not give H₂ with dilute HCl.

3 marks: “Explain why E°(Mn³⁺/Mn²⁺) is highly positive, E°(Fe³⁺/Fe²⁺) is comparatively low, and E°(Cr³⁺/Cr²⁺) is negative.” Mn²⁺ is the stable d⁵, so Mn³⁺ is easily reduced. Fe³⁺ is also d⁵, so it resists reduction. Cr³⁺ (d³, half-filled t₂g) is stable, so Cr²⁺ is easily oxidised.

2 marks: “Cr²⁺ is reducing and Mn³⁺ is oxidising, though both are d⁴. Explain.” Cr²⁺ → Cr³⁺ gives d³ (half-filled t₂g, stable). Mn³⁺ → Mn²⁺ gives d⁵ (half-filled, stable). Each moves to its own stable configuration.

Remember it

Copper is the odd plus one. Ions rush towards d³, d⁵ or d¹⁰: Cr²⁺ gives, Mn³⁺ takes.