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Unit VIII · Aldehydes, ketones and carboxylic acids
12 min readPathway sheet1-mark MCQ on names or boiling points; 2 or 3-mark preparation equations (from alkylbenzenes, nitriles, Grignard reagents, esters); also a NEET favourite

Carboxylic acids: naming, structure, preparation and physical properties

Carboxylic acids (-COOH) are made by oxidising alcohols, aldehydes or alkylbenzenes, or by hydrolysing nitriles, amides and esters. Hydrogen-bonded dimers give them high boiling points.

Carboxyl group-COOH; the carboxyl carbon is sp², with its three σ bonds in one plane about 120° apart
IUPAC endings-oic acid (ethanoic acid); two groups: -dioic acid (hexanedioic acid); on a ring: -carboxylic acid
Grignard routeRMgX + CO₂ (dry ice), then H₃O⁺ → RCOOH, one carbon more than RX
Boiling pointHigher than alcohols of similar molar mass: ethanoic acid 391 K, propan-1-ol 370 K

Common and IUPAC names

FormulaCommon nameIUPAC name
HCOOHFormic acid (from ants; Latin formica)Methanoic acid
CH₃COOHAcetic acid (from vinegar; Latin acetum)Ethanoic acid
CH₃CH₂COOHPropionic acidPropanoic acid
CH₃CH₂CH₂COOHButyric acid (from rancid butter; Latin butyrum)Butanoic acid
(CH₃)₂CHCOOHIsobutyric acid (α-methylpropionic acid)2-Methylpropanoic acid
HOOC-COOHOxalic acidEthanedioic acid
HOOC-CH₂-COOHMalonic acidPropanedioic acid
HOOC-(CH₂)₄-COOHAdipic acidHexanedioic acid (the 'e' of hexane stays)
C₆H₅COOHBenzoic acidBenzenecarboxylic acid (benzoic acid is also accepted)
C₆H₅CH₂COOHPhenylacetic acid2-Phenylethanoic acid
C₆H₄(COOH)₂, groups on C1 and C2Phthalic acidBenzene-1,2-dicarboxylic acid

Structure of the carboxyl group

The carboxyl group, -COOH, is a carbonyl group joined to an -OH group. The carboxyl carbon is sp²: its three σ bonds lie in one plane, about 120° apart. A lone pair on the -OH oxygen is shared with the C=O group by resonance. Because of this, the carboxyl carbon is less electrophilic than the carbonyl carbon of an aldehyde or ketone. So carboxylic acids do not give the usual addition reactions of C=O, such as those with 2,4-DNP or NaHSO₃.

Methods of preparation

  1. 1★
    From primary alcohols and aldehydes: RCH₂OH → (i) alkaline KMnO₄ (ii) H₃O⁺ → RCOOH; CH₃(CH₂)₈CH₂OH → (CrO₃, H₂SO₄) CH₃(CH₂)₈COOH
    KMnO₄ (neutral, acidic or alkaline), K₂Cr₂O₇ or CrO₃ in acid (Jones reagent) all work. Aldehydes are oxidised even more easily
  2. 2★
    From alkylbenzenes: C₆H₅CH₃ → (KMnO₄, KOH, heat) C₆H₅COOK → (H₃O⁺) C₆H₅COOH
    Chromic acid or KMnO₄ oxidises the whole side chain to -COOH, whatever its length. Primary and secondary alkyl groups react; a tertiary alkyl group does not
  3. 3
    From nitriles and amides: RCN → (H₂O, H⁺ or OH⁻) RCONH₂ → (H₂O, H⁺ or OH⁻) RCOOH; CH₃CONH₂ + H₂O → (H⁺) CH₃COOH + NH₃
    Under mild conditions, the reaction stops at the amide
  4. 4★
    From Grignard reagents: RMgX + CO₂ (dry ice) → (dry ether) RCOOMgX → (H₃O⁺) RCOOH
    The acid has one carbon more than the alkyl halide. Nitriles, made from RX and CN⁻, also add one carbon
  5. 5
    From acyl halides and anhydrides: RCOCl + H₂O → RCOOH + HCl; (CH₃CO)₂O + H₂O → 2CH₃COOH
    Acyl chlorides react faster with aqueous base, giving RCOO⁻, which gives the acid on acidifying
  6. 6
    From esters: C₆H₅COOC₂H₅ + NaOH → (heat) C₆H₅COONa + C₂H₅OH; C₆H₅COONa + HCl → C₆H₅COOH + NaCl
    Acid hydrolysis gives the acid directly: CH₃CH₂CH₂COOC₂H₅ + H₂O ⇌ (H⁺) CH₃CH₂CH₂COOH + C₂H₅OH

★ key step

Worked example: choose a route

Problem

How will you prepare: (i) benzoic acid from toluene (ii) propanoic acid from bromoethane, by two routes (iii) benzene-1,4-dicarboxylic acid from 1-ethyl-4-methylbenzene?

Working
  1. (i) Heat toluene with alkaline KMnO₄ to get potassium benzoate; acidify with H₃O⁺ to get benzoic acid.
  2. (ii) Bromoethane has 2 carbons; propanoic acid has 3, so one carbon must be added.
  3. Route A: CH₃CH₂Br + KCN (ethanolic) → CH₃CH₂CN + KBr; then hydrolyse with H₃O⁺ → CH₃CH₂COOH.
  4. Route B: CH₃CH₂Br + Mg (dry ether) → CH₃CH₂MgBr; add CO₂ (dry ice); then H₃O⁺ → CH₃CH₂COOH.
  5. (iii) Heat 4-CH₃C₆H₄CH₂CH₃ with alkaline KMnO₄, then acidify. Both side chains (-CH₃ and -CH₂CH₃) are oxidised to -COOH, whatever their length: HOOC-C₆H₄-COOH.
Answer

(i) KMnO₄/KOH, heat, then H₃O⁺. (ii) KCN then hydrolysis, or Mg/dry ether then CO₂ and H₃O⁺. (iii) KMnO₄/KOH, heat, then H₃O⁺.

Physical properties and the reasons

PropertyWhat you seeWhy
State and smellAliphatic acids with up to 9 carbons are colourless liquids with unpleasant smells; higher acids are wax-like, almost odourless solidsHigher acids are not volatile
Boiling pointHigher than aldehydes, ketones and even alcohols of similar molar massStrong, extensive intermolecular hydrogen bonding; most acids exist as dimers, even in the vapour phase and in aprotic solvents
Example data (molar mass 60)Ethanoic acid 391 K; propan-1-ol 370 KTwo hydrogen bonds hold each pair of acid molecules
Solubility in waterAcids with 1 to 4 carbons mix with water; solubility falls as the chain grows; benzoic acid is nearly insoluble in cold waterHydrogen bonds with water; the large non-polar part is hydrophobic
Other solventsDissolve in less polar solvents such as benzene, ether, alcohol and chloroformThe hydrocarbon part mixes with these solvents

How to draw the hydrogen-bonded dimer

  • Draw two RCOOH molecules side by side, facing each other.
  • Place the C=O of one molecule opposite the O-H of the other, and the O-H of the first opposite the C=O of the second.
  • Join each O-H hydrogen to the C=O oxygen across from it with a dotted line: these are the two hydrogen bonds.
  • The two molecules now form an eight-membered ring.
  • Label: R, C=O, O-H, 'hydrogen bond' (on both dotted lines) and 'dimer'.
In real life

The sour taste of vinegar in pickles is ethanoic acid, and the sting of a red ant bite is partly methanoic acid. Butanoic acid gives rancid butter or old ghee its bad smell.

Exam angle

2 marks: “Write the IUPAC names of (i) (CH₃)₂CHCOOH (ii) HOOC(CH₂)₄COOH.” (i) 2-Methylpropanoic acid. (ii) Hexanedioic acid (adipic acid).

3 marks: “How will you prepare benzoic acid from (i) toluene (ii) phenylmagnesium bromide (iii) ethyl benzoate? Write the equations.” (i) C₆H₅CH₃ → (KMnO₄/KOH, heat) C₆H₅COOK → (H₃O⁺) C₆H₅COOH. (ii) C₆H₅MgBr + CO₂ → C₆H₅COOMgBr → (H₃O⁺) C₆H₅COOH. (iii) C₆H₅COOC₂H₅ + NaOH → C₆H₅COONa + C₂H₅OH, then HCl → C₆H₅COOH.

2 marks: “Why do carboxylic acids have higher boiling points than alcohols of comparable molar mass?” Carboxylic acid molecules are held in pairs (dimers) by two hydrogen bonds. These are stronger and more extensive than in alcohols and are not fully broken even in the vapour phase.

Remember it

Oxidise, hydrolyse, or add CO₂. Grignard + CO₂ and RX + CN⁻ both add one carbon.