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Unit VIII · Aldehydes, ketones and carboxylic acids
10 min readConcept sheet1-mark MCQ on names or boiling points; 2-mark 'write the IUPAC name' or 'arrange in order of boiling point'

Aldehydes and ketones: naming, structure, physical properties and uses

Aldehydes (-CHO) and ketones (C=O between two carbons) share the carbonyl group. Its polar C=O bond explains their boiling points and solubility.

Carbonyl carbonsp² hybridised, trigonal planar, bond angles about 120°
Aldehyde ending-al, as in ethanal (CH₃CHO); a CHO on a ring takes -carbaldehyde
Ketone ending-one, as in propanone (CH₃COCH₃) and butan-2-one
Boiling point orderFor similar molar mass: alkane < ether < aldehyde, ketone < alcohol

The carbonyl group

The carbonyl group is a carbon joined to an oxygen by a double bond, >C=O. In an aldehyde, the carbonyl carbon is bonded to at least one hydrogen (-CHO). In a ketone, it is bonded to two carbon groups. The carbonyl carbon is sp² hybridised. It forms three σ (sigma) bonds that lie in one plane at about 120°. Its leftover p orbital overlaps with a p orbital of oxygen to form a π bond. Oxygen is more electronegative than carbon, so the electrons are pulled towards oxygen. The C=O bond is therefore polar: carbon carries a partial positive charge (δ+) and oxygen a partial negative charge (δ−). We show this with resonance: >C=O ↔ >C⁺-O⁻. So the carbonyl carbon is an electrophile (a Lewis acid, it accepts electrons), and the oxygen is a nucleophile (a Lewis base). Aldehydes and ketones have large dipole moments, larger than ethers.

Common and IUPAC names

FormulaCommon nameIUPAC name
HCHOFormaldehydeMethanal
CH₃CHOAcetaldehydeEthanal
(CH₃)₂CHCHOIsobutyraldehyde (α-methylpropionaldehyde)2-Methylpropanal
(CH₃)₂CHCH₂CHOIsovaleraldehyde (β-methylbutyraldehyde)3-Methylbutanal
CH₃CH=CHCHOCrotonaldehydeBut-2-enal
C₆H₅CHOBenzaldehydeBenzenecarbaldehyde (benzaldehyde is also accepted)
C₆H₁₁CHO (CHO on a cyclohexane ring)No common nameCyclohexanecarbaldehyde
CH₃COCH₃AcetonePropanone
CH₃COCH₂CH₃Ethyl methyl ketoneButan-2-one
CH₃COCH₂CH(CH₃)₂Isobutyl methyl ketone4-Methylpentan-2-one
C₆H₅COCH₃Acetophenone1-Phenylethanone
C₆H₅COC₆H₅BenzophenoneDiphenylmethanone

How to write the IUPAC name

  1. 1
    Choose the longest chain that contains the carbonyl carbon. In an aldehyde, the CHO carbon is always C1.
  2. 2★
    Replace the final 'e' of the alkane name with -al (aldehyde) or -one (ketone).
    Propane becomes propanal or propanone
  3. 3
    For a ketone, number the chain so the C=O carbon gets the lowest number, and write that number before -one: butan-2-one.
  4. 4
    Name and number the substituents and write them as prefixes in alphabetical order: 6-chloro-4-ethylhexan-3-one.
  5. 5
    If the CHO group is attached to a ring, use the suffix -carbaldehyde; the CHO carbon is not counted in the ring.
    Cyclohexanecarbaldehyde, benzenecarbaldehyde
  6. 6
    In common names, the carbon next to C=O is α, the next is β, and so on. IUPAC names use numbers instead.
    β-Methylbutyraldehyde = 3-methylbutanal

★ key step

Worked example: name these compounds

Problem

Give the IUPAC names of: (i) CH₃CH₂CH(CH₃)CH₂CHO (ii) CH₃COCH₂CH₂COCH₃ (iii) CH₃CH=CHCH₂CHO (iv) CH₃CH₂COCH(CH₃)CH₂CH₂Br

Working
  1. (i) The chain has 5 carbons, counting the CHO carbon as C1. The methyl group is on C3. Name: 3-methylpentanal.
  2. (ii) The chain has 6 carbons with C=O at C2 and C5. Two -one groups make -dione, and the 'e' of hexane stays before a consonant. Name: hexane-2,5-dione.
  3. (iii) The chain has 5 carbons: CHO is C1, and the double bond is between C3 and C4. Name: pent-3-enal.
  4. (iv) The longest chain runs through the CH₂CH₂Br end: 6 carbons. Numbering from the CH₃CH₂ end puts C=O at C3 (from the other end it would be C4). The methyl is on C4 and Br on C6. Alphabetical order: bromo before methyl. Name: 6-bromo-4-methylhexan-3-one.
Answer

3-Methylpentanal; hexane-2,5-dione; pent-3-enal; 6-bromo-4-methylhexan-3-one

Physical properties and the reasons

PropertyWhat you seeWhy
StateMethanal is a gas; ethanal is a volatile liquid; most others are liquids or solids at room temperatureLarger molecules attract each other more strongly
Boiling point compared with hydrocarbons and ethersHigherThe polar C=O gives dipole-dipole attraction between molecules
Boiling point compared with alcoholsLowerNo O-H bond, so no intermolecular hydrogen bonding
Example data (molar mass 58 to 60)n-Butane 273 K, methoxyethane 281 K, propanal 322 K, propanone 329 K, propan-1-ol 370 KOrder: alkane < ether < aldehyde, ketone < alcohol
Solubility in waterMethanal, ethanal and propanone mix with water in all proportions; solubility falls as the chain growsThe C=O oxygen forms hydrogen bonds with water; a long alkyl chain is non-polar
SmellLower aldehydes smell sharp and pungent; larger aldehydes and many ketones smell pleasantSo many are used in perfumes and flavours

Uses of aldehydes and ketones

  • Formalin, about a 40% solution of methanal in water, preserves biological specimens.
  • Methanal is used to make bakelite (a phenol-formaldehyde resin), urea-formaldehyde glues and other polymers.
  • Ethanal is a starting material for ethanoic acid, ethyl ethanoate, vinyl ethanoate, polymers and drugs.
  • Benzaldehyde is used in perfumes and in making dyes.
  • Propanone (acetone) and butan-2-one (ethyl methyl ketone) are common industrial solvents. Acetone is in nail polish remover.
  • Many natural smells and flavours are carbonyl compounds: vanillin (vanilla beans), cinnamaldehyde (cinnamon), salicylaldehyde (meadowsweet), and camphor, a ketone.
In real life

The warm smell of dalchini (cinnamon) in a biryani comes from cinnamaldehyde, and vanilla ice cream gets its flavour from vanillin. The acetone in nail polish remover is a ketone used as a solvent.

Exam angle

2 marks: “Write the IUPAC names of (i) CH₃COCH₂CH(CH₃)₂ (ii) C₆H₅COCH₃.” (i) 4-Methylpentan-2-one: a 5-carbon chain, C=O at C2, methyl at C4. (ii) 1-Phenylethanone (acetophenone).

2 marks: “Arrange in increasing order of boiling point and give a reason: CH₃CH₂CH₂OH, CH₃COCH₃, CH₃CH₂CH₂CH₃, CH₃OCH₂CH₃.” CH₃CH₂CH₂CH₃ (273 K) < CH₃OCH₂CH₃ (281 K) < CH₃COCH₃ (329 K) < CH₃CH₂CH₂OH (370 K). Butane has only weak dispersion forces; the ether is weakly polar; propanone has strong dipole-dipole attraction; propan-1-ol forms intermolecular hydrogen bonds.

3 marks: “Why is the carbonyl group polar? Why do the lower aldehydes and ketones dissolve in water while the higher ones do not?” O is more electronegative, so C=O is polar: C is δ+, O is δ−. Lower members form hydrogen bonds with water through the C=O oxygen. In higher members, the large non-polar alkyl part outweighs this, so solubility falls.

Remember it

-al for aldehyde, -one for ketone. Boiling points climb with attraction: alkane < ether < carbonyl < alcohol.