haya.Learning made clear
Unit VI · Haloalkanes and haloarenes
12 min readPathway sheet1-mark MCQ and assertion-reason on reactivity order; 3-mark mechanism of SN1 or SN2; often part of a 5-mark answer or a case-based question; also a NEET and JEE favourite

Nucleophilic substitution: SN2 and SN1

A nucleophile replaces the halide ion. SN2 is one step with backside attack (CH₃X fastest); SN1 goes through a carbocation (3° fastest).

NucleophileAn electron-rich species (an anion or a molecule with a lone pair) that attacks an electron-poor carbon, e.g. OH⁻, CN⁻, NH₃
SN2One step; rate = k[RX][Nu⁻]; reactivity CH₃X > 1° > 2° > 3°
SN1Two steps through a carbocation; rate = k[RX]; reactivity 3° > 2° > 1° > CH₃X
Effect of the halogenSame in both: R-I > R-Br > R-Cl >> R-F

Common nucleophiles and products (R-X + Nu)

ReagentNucleophileProductClass of product
NaOH or KOH (aq)HO⁻R-OHAlcohol
H₂OH₂OR-OHAlcohol
NaOR'R'O⁻R-O-R'Ether
NaII⁻R-IAlkyl iodide
NH₃NH₃R-NH₂Primary amine
R'NH₂R'NH₂R-NH-R'Secondary amine
KCNC≡N⁻ (attacks through C)R-CNNitrile (alkyl cyanide)
AgCNAg-CN (only the N end is free, so it attacks through N)R-NCIsonitrile (isocyanide)
KNO₂O=N-O⁻ (attacks through O)R-O-N=OAlkyl nitrite
AgNO₂Ag-O-N=O (attacks through N)R-NO₂Nitroalkane
R'COOAgR'COO⁻R'COOREster
LiAlH₄H⁻R-HHydrocarbon
R'⁻M⁺R'⁻R-R'Alkane

Ambident nucleophiles

Some nucleophiles can attack through two different atoms; they are called ambident nucleophiles. Cyanide can use C or N. KCN is mainly ionic, so free CN⁻ attacks through carbon (a C-C bond is more stable than C-N) and gives an alkyl cyanide, R-CN. AgCN is mainly covalent, so only the nitrogen is free to donate its electron pair, giving an isocyanide, R-NC. Nitrite behaves the same way: KNO₂ gives an alkyl nitrite, R-O-N=O, while AgNO₂ gives a nitroalkane, R-NO₂.

SN2 mechanism

SN2 means substitution, nucleophilic, bimolecular: two species take part in the only step. Example: CH₃Cl with OH⁻ (proposed by Hughes and Ingold, 1937).

  1. 1
    OH⁻ approaches the carbon from the side opposite the chlorine (backside attack).
  2. 2
    Transition state: HO···CH₃···Cl. The C-O bond forms while the C-Cl bond breaks, all in one step. The three H atoms lie flat in one plane.
    A transition state is the unstable arrangement at the top of the energy hill; it cannot be isolated
  3. 3★
    CH₃Cl + OH⁻ → CH₃OH + Cl⁻
    Cl⁻ leaves. The three H atoms flip over like an umbrella blown inside out: inversion of configuration
  4. 4
    Rate = k[CH₃Cl][OH⁻], second order. Bulky groups near the carbon block the attack (steric hindrance), so CH₃X > 1° > 2° > 3°.

★ key step

SN1 mechanism

SN1 means substitution, nucleophilic, unimolecular: only the alkyl halide takes part in the slow step. It is favoured in **polar protic solvents** (water, alcohol, ethanoic acid), which stabilise the ions. Example: (CH₃)₃CBr with OH⁻.

  1. 1★
    (CH₃)₃C-Br → (CH₃)₃C⁺ + Br⁻
    Slow, rate-determining step: the C-Br bond breaks to give a carbocation
  2. 2
    (CH₃)₃C⁺ + OH⁻ → (CH₃)₃C-OH
    Fast step: the nucleophile joins the carbocation
  3. 3
    Rate = k[(CH₃)₃CBr], first order. Carbocation stability is 3° > 2° > 1° > CH₃⁺ (alkyl groups push electrons towards the positive carbon), so 3° halides react fastest.
  4. 4
    Allylic and benzylic halides also react fast by SN1, because their carbocations are stabilised by resonance.

★ key step

SN2 vs SN1

SN2One step, no intermediate. Rate depends on [RX] and [Nu⁻]. Favoured by CH₃X and 1° halides and a strong nucleophile. Gives inversion.
SN1Two steps through a carbocation. Rate depends on [RX] only. Favoured by 3°, allylic and benzylic halides in a polar protic solvent. Gives racemisation with an optically active halide.

SN2 is decided by crowding at the carbon; SN1 is decided by how stable the carbocation is.

In real life

Nucleophilic substitution is how chemists attach -OH, -CN or -NH₂ groups to a carbon chain. Many medicines and dyes made by India's chemical industry begin with a step like this.

Exam angle

3 marks: “Write the SN2 mechanism for the reaction of chloromethane with hydroxide ion. Why is it called SN2?” OH⁻ attacks from the back; transition state HO···CH₃···Cl; Cl⁻ leaves and the configuration inverts. Rate = k[CH₃Cl][OH⁻]: two species in the rate-determining step, so bimolecular (SN2).

2 marks: “Bromoethane gives propanenitrile with KCN but ethyl isocyanide with AgCN. Explain.” Cyanide is ambident. KCN is ionic; free CN⁻ attacks through C (C-C bond more stable), giving CH₃CH₂CN. AgCN is covalent; only N's lone pair is free, so CH₃CH₂NC forms.

2 marks: “Arrange in increasing order of SN1 reactivity, with a reason: CH₃CH₂Br, (CH₃)₃CBr, (CH₃)₂CHBr.” CH₃CH₂Br < (CH₃)₂CHBr < (CH₃)₃CBr, because carbocation stability is 1° < 2° < 3°.

Remember it

SN2: two in the slow step, one step overall, back door, flip. SN1: one in the slow step, two steps overall, carbocation, mix.