Reactions of phenols, and tests for alcohols and phenols
The -OH group activates the ring and directs to ortho and para. Phenol is brominated, nitrated, carboxylated (Kolbe's reaction) and formylated (Reimer-Tiemann reaction).
Nitration
The -OH group **activates** the ring and is **ortho-para directing**: its lone pair raises the electron density at the ortho and para positions by resonance.
- 1C₆H₅OH + HNO₃ → 2-nitrophenol or 4-nitrophenol, + H₂ODilute HNO₃ at 298 K
- 2★Separate the isomers by steam distillation. o-Nitrophenol is steam volatile because of intramolecular hydrogen bonding (within one molecule). p-Nitrophenol is less volatile because intermolecular hydrogen bonds link its molecules.
- 3C₆H₅OH + 3HNO₃ → C₆H₂(NO₂)₃OH + 3H₂OConc HNO₃ gives 2,4,6-trinitrophenol (picric acid), but in poor yield
- 4Better route to picric acid: phenol + conc H₂SO₄ → phenol-2,4-disulphonic acid; then conc HNO₃ → 2,4,6-trinitrophenol.
★ key step
Halogenation
- 1C₆H₅OH + Br₂ → 4-bromophenol (major) or 2-bromophenol (minor), + HBrBromine in a solvent of low polarity (CHCl₃ or CS₂), at low temperature (273 K)
- 2★C₆H₅OH + 3Br₂ → C₆H₂Br₃OH + 3HBrBromine water: the orange colour fades and a white precipitate of 2,4,6-tribromophenol forms
- 3No Lewis acid is needed. The strongly activating -OH group makes Br₂ polarise on its own, unlike benzene, which needs FeBr₃.
★ key step
Kolbe's reaction
- 1C₆H₅OH + NaOH → C₆H₅ONa + H₂OThe phenoxide ion is even more reactive than phenol towards electrophiles
- 2★C₆H₅ONa + CO₂ → HOC₆H₄COONa (sodium salicylate)CO₂, a weak electrophile, under pressure on heating (typical values, not given in your textbook: about 400 K and 4 to 7 atm). It enters the ortho position
- 3HOC₆H₄COONa + HCl → HOC₆H₄COOH + NaClAcidify: salicylic acid (2-hydroxybenzoic acid) is the main product
★ key step
Reimer-Tiemann reaction
A -CHO (formyl) group is brought into the ortho position of phenol.
- 1Warm phenol with CHCl₃ and aqueous NaOH (about 340 K is typical; your textbook gives no temperature). A -CHCl₂ group enters the ortho position of the phenoxide ion, giving an intermediate (a substituted benzal chloride).
- 2★The alkali hydrolyses -CHCl₂ to -CHO, giving the sodium salt of salicylaldehyde. Overall: C₆H₅OH + CHCl₃ + 4NaOH → NaOC₆H₄CHO + 3NaCl + 3H₂O
- 3NaOC₆H₄CHO + HCl → HOC₆H₄CHO + NaClAcidify: salicylaldehyde (2-hydroxybenzaldehyde)
★ key step
Two more reactions of phenol
- 1C₆H₅OH + Zn → C₆H₆ + ZnOHeat with zinc dust: phenol is reduced to benzene. This is the only C-O bond cleavage that phenols show
- 2C₆H₅OH + 2[O] → C₆H₄O₂ (benzoquinone) + H₂OChromic acid (Na₂Cr₂O₇ with H₂SO₄) oxidises phenol to benzoquinone, a conjugated diketone. In air, phenols slowly darken as coloured quinones form
Activity: tests for alcoholic and phenolic -OH groups
- 1Sodium metal test (alcohols and phenols): add a small piece of dry sodium to 1 mL of the dry liquid. Brisk effervescence of hydrogen shows an -OH group.2R-OH + 2Na → 2R-ONa + H₂
- 2Ester test (alcohols): warm 1 mL of the liquid with 1 mL of ethanoic acid and 1 to 2 drops of conc H₂SO₄, then pour into water. A fruity smell shows an alcohol.
- 3Ceric ammonium nitrate test (alcohols): add a few drops of the reagent and shake. A red colour shows an alcoholic -OH; it fades on standing or with excess reagent.
- 4Iodoform test: warm with iodine and NaOH solution. A yellow precipitate of CHI₃ shows ethanol, or a 2° alcohol with a CH₃CH(OH)- group. Methanol does not give it.CH₃CH₂OH + 4I₂ + 6NaOH → CHI₃ + HCOONa + 5NaI + 5H₂O
- 5Lucas test tells 1°, 2° and 3° alcohols apart (see the reactions of alcohols).
- 6★Litmus and ferric chloride tests (phenols): phenol turns blue litmus faintly red. With neutral FeCl₃ solution it gives a violet colour.6C₆H₅OH + FeCl₃ → [Fe(OC₆H₅)₆]³⁻ + 3H⁺ + 3HCl
- 7Bromine water test (phenols): the orange colour fades and a white precipitate forms.
- 8Phthalein dye test (phenols): heat a little of the compound with phthalic anhydride and 1 to 2 drops of conc H₂SO₄ for a minute; cool and pour into dilute NaOH. Phenol gives a dark pink colour (phenolphthalein); other phenols give other colours. Record each test in three columns: experiment, observation, inference.
★ key step
Salicylic acid from Kolbe's reaction goes into anti-dandruff shampoos and acne creams and is turned into aspirin. Salicylaldehyde from the Reimer-Tiemann reaction is used to make the sweet-smelling compound coumarin for perfumes.
2 marks: “Phenol is turned into 2-hydroxybenzoic acid in stages using NaOH and CO₂. Write the equations and name the reaction.” C₆H₅OH + NaOH → C₆H₅ONa + H₂O; C₆H₅ONa + CO₂ (heat, pressure) → HOC₆H₄COONa (sodium salicylate); HOC₆H₄COONa + HCl → HOC₆H₄COOH + NaCl. Product: salicylic acid (2-hydroxybenzoic acid).
2 marks: “How is 2-hydroxybenzaldehyde made from phenol and chloroform? Name the reaction and write its steps.” Phenol + CHCl₃ + aqueous NaOH (warm) → intermediate with -CHCl₂ at ortho → hydrolysed to sodium salicylaldehyde; H⁺ → salicylaldehyde (2-hydroxybenzaldehyde).
3 marks: “What happens when phenol is treated with (i) bromine water, (ii) dilute HNO₃, (iii) conc HNO₃? How are the products of (ii) separated, and why?” (i) 2,4,6-tribromophenol, white precipitate. (ii) o- and p-nitrophenol; steam distillation, as o-nitrophenol is steam volatile (intramolecular H-bond). (iii) 2,4,6-trinitrophenol (picric acid).
Kolbe brings CO₂ (an acid group); Reimer-Tiemann brings CHCl₃ (an aldehyde group). Both land at ortho.