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Unit VII · Alcohols, phenols and ethers
12 min readPathway sheetKolbe's and Reimer-Tiemann reactions as 2-mark favourites; bromination and nitration in 1-mark MCQs and assertion-reason; 3 or 5-mark conversions; tests in the practical and case-based questions; also a NEET favourite

Reactions of phenols, and tests for alcohols and phenols

The -OH group activates the ring and directs to ortho and para. Phenol is brominated, nitrated, carboxylated (Kolbe's reaction) and formylated (Reimer-Tiemann reaction).

Bromine water + phenolC₆H₅OH + 3Br₂ → 2,4,6-tribromophenol (white precipitate) + 3HBr; no catalyst needed
Kolbe's reactionSodium phenoxide + CO₂, then H⁺ → salicylic acid (2-hydroxybenzoic acid)
Reimer-Tiemann reactionPhenol + CHCl₃ + aqueous NaOH, then H⁺ → salicylaldehyde (2-hydroxybenzaldehyde)
Ferric chloride testPhenol gives a violet colour with neutral FeCl₃ solution

Nitration

The -OH group **activates** the ring and is **ortho-para directing**: its lone pair raises the electron density at the ortho and para positions by resonance.

  1. 1
    C₆H₅OH + HNO₃ → 2-nitrophenol or 4-nitrophenol, + H₂O
    Dilute HNO₃ at 298 K
  2. 2★
    Separate the isomers by steam distillation. o-Nitrophenol is steam volatile because of intramolecular hydrogen bonding (within one molecule). p-Nitrophenol is less volatile because intermolecular hydrogen bonds link its molecules.
  3. 3
    C₆H₅OH + 3HNO₃ → C₆H₂(NO₂)₃OH + 3H₂O
    Conc HNO₃ gives 2,4,6-trinitrophenol (picric acid), but in poor yield
  4. 4
    Better route to picric acid: phenol + conc H₂SO₄ → phenol-2,4-disulphonic acid; then conc HNO₃ → 2,4,6-trinitrophenol.

★ key step

Halogenation

  1. 1
    C₆H₅OH + Br₂ → 4-bromophenol (major) or 2-bromophenol (minor), + HBr
    Bromine in a solvent of low polarity (CHCl₃ or CS₂), at low temperature (273 K)
  2. 2★
    C₆H₅OH + 3Br₂ → C₆H₂Br₃OH + 3HBr
    Bromine water: the orange colour fades and a white precipitate of 2,4,6-tribromophenol forms
  3. 3
    No Lewis acid is needed. The strongly activating -OH group makes Br₂ polarise on its own, unlike benzene, which needs FeBr₃.

★ key step

Kolbe's reaction

  1. 1
    C₆H₅OH + NaOH → C₆H₅ONa + H₂O
    The phenoxide ion is even more reactive than phenol towards electrophiles
  2. 2★
    C₆H₅ONa + CO₂ → HOC₆H₄COONa (sodium salicylate)
    CO₂, a weak electrophile, under pressure on heating (typical values, not given in your textbook: about 400 K and 4 to 7 atm). It enters the ortho position
  3. 3
    HOC₆H₄COONa + HCl → HOC₆H₄COOH + NaCl
    Acidify: salicylic acid (2-hydroxybenzoic acid) is the main product

★ key step

Reimer-Tiemann reaction

A -CHO (formyl) group is brought into the ortho position of phenol.

  1. 1
    Warm phenol with CHCl₃ and aqueous NaOH (about 340 K is typical; your textbook gives no temperature). A -CHCl₂ group enters the ortho position of the phenoxide ion, giving an intermediate (a substituted benzal chloride).
  2. 2★
    The alkali hydrolyses -CHCl₂ to -CHO, giving the sodium salt of salicylaldehyde. Overall: C₆H₅OH + CHCl₃ + 4NaOH → NaOC₆H₄CHO + 3NaCl + 3H₂O
  3. 3
    NaOC₆H₄CHO + HCl → HOC₆H₄CHO + NaCl
    Acidify: salicylaldehyde (2-hydroxybenzaldehyde)

★ key step

Two more reactions of phenol

  1. 1
    C₆H₅OH + Zn → C₆H₆ + ZnO
    Heat with zinc dust: phenol is reduced to benzene. This is the only C-O bond cleavage that phenols show
  2. 2
    C₆H₅OH + 2[O] → C₆H₄O₂ (benzoquinone) + H₂O
    Chromic acid (Na₂Cr₂O₇ with H₂SO₄) oxidises phenol to benzoquinone, a conjugated diketone. In air, phenols slowly darken as coloured quinones form

Activity: tests for alcoholic and phenolic -OH groups

  1. 1
    Sodium metal test (alcohols and phenols): add a small piece of dry sodium to 1 mL of the dry liquid. Brisk effervescence of hydrogen shows an -OH group.
    2R-OH + 2Na → 2R-ONa + H₂
  2. 2
    Ester test (alcohols): warm 1 mL of the liquid with 1 mL of ethanoic acid and 1 to 2 drops of conc H₂SO₄, then pour into water. A fruity smell shows an alcohol.
  3. 3
    Ceric ammonium nitrate test (alcohols): add a few drops of the reagent and shake. A red colour shows an alcoholic -OH; it fades on standing or with excess reagent.
  4. 4
    Iodoform test: warm with iodine and NaOH solution. A yellow precipitate of CHI₃ shows ethanol, or a 2° alcohol with a CH₃CH(OH)- group. Methanol does not give it.
    CH₃CH₂OH + 4I₂ + 6NaOH → CHI₃ + HCOONa + 5NaI + 5H₂O
  5. 5
    Lucas test tells 1°, 2° and 3° alcohols apart (see the reactions of alcohols).
  6. 6★
    Litmus and ferric chloride tests (phenols): phenol turns blue litmus faintly red. With neutral FeCl₃ solution it gives a violet colour.
    6C₆H₅OH + FeCl₃ → [Fe(OC₆H₅)₆]³⁻ + 3H⁺ + 3HCl
  7. 7
    Bromine water test (phenols): the orange colour fades and a white precipitate forms.
  8. 8
    Phthalein dye test (phenols): heat a little of the compound with phthalic anhydride and 1 to 2 drops of conc H₂SO₄ for a minute; cool and pour into dilute NaOH. Phenol gives a dark pink colour (phenolphthalein); other phenols give other colours. Record each test in three columns: experiment, observation, inference.

★ key step

In real life

Salicylic acid from Kolbe's reaction goes into anti-dandruff shampoos and acne creams and is turned into aspirin. Salicylaldehyde from the Reimer-Tiemann reaction is used to make the sweet-smelling compound coumarin for perfumes.

Exam angle

2 marks: “Phenol is turned into 2-hydroxybenzoic acid in stages using NaOH and CO₂. Write the equations and name the reaction.” C₆H₅OH + NaOH → C₆H₅ONa + H₂O; C₆H₅ONa + CO₂ (heat, pressure) → HOC₆H₄COONa (sodium salicylate); HOC₆H₄COONa + HCl → HOC₆H₄COOH + NaCl. Product: salicylic acid (2-hydroxybenzoic acid).

2 marks: “How is 2-hydroxybenzaldehyde made from phenol and chloroform? Name the reaction and write its steps.” Phenol + CHCl₃ + aqueous NaOH (warm) → intermediate with -CHCl₂ at ortho → hydrolysed to sodium salicylaldehyde; H⁺ → salicylaldehyde (2-hydroxybenzaldehyde).

3 marks: “What happens when phenol is treated with (i) bromine water, (ii) dilute HNO₃, (iii) conc HNO₃? How are the products of (ii) separated, and why?” (i) 2,4,6-tribromophenol, white precipitate. (ii) o- and p-nitrophenol; steam distillation, as o-nitrophenol is steam volatile (intramolecular H-bond). (iii) 2,4,6-trinitrophenol (picric acid).

Remember it

Kolbe brings CO₂ (an acid group); Reimer-Tiemann brings CHCl₃ (an aldehyde group). Both land at ortho.