Torque on a dipole in a uniform electric field
In a uniform field a dipole feels zero net force but a torque τ = p × E, which turns it to line up with the field.
Derivation: torque on a dipole
A dipole (−q at A, +q at B, AB = 2a) sits in a uniform field E, with p at an angle θ to E.
- 1Force on +q: qE, along E. Force on −q: qE, opposite to E.
- 2The forces are equal and opposite, so the net force is zero. The dipole does not move as a whole.
- 3But the two forces act along different lines. They form a couple, which turns the dipole.
- 4Torque = one force × perpendicular distance between their lines of action = qE × 2a sin θ.
- 5Since p = q × 2a: τ = pE sin θ.
- 6★So, in vector form τ = p × E. It is perpendicular to the plane of p and E, and it tries to turn p into line with E.
★ key step
How to draw the figure
- 1Draw several parallel horizontal arrows for the uniform field E.
- 2Draw the dipole AB tilted at angle θ to the field: −q at A, +q at B. Mark p from A to B.
- 3At B draw an arrow qE along the field. At A draw an arrow qE opposite to the field.
- 4Drop a perpendicular from B to the field line through A, and label it 2a sin θ.
Torque at different angles
| Angle θ between p and E | Torque τ = pE sin θ | What it means |
|---|---|---|
| 0° | 0 | p along E: stable equilibrium |
| 30° | pE/2 | Half the maximum torque |
| 90° | pE (maximum) | p at right angles to E |
| 180° | 0 | p against E: unstable equilibrium |
Dipole in a non-uniform field
In a non-uniform field, the forces on +q and −q are no longer equal. So there is a net force as well as a torque. If p points along E, the dipole is pulled towards the region of stronger field. If p points against E, it is pushed towards the weaker field. This explains why a comb charged by dry hair attracts bits of paper. The comb's field polarises the paper, making tiny dipoles along the field. The comb's field is non-uniform, so the paper is pulled towards the comb.
Worked example: torque on a dipole
(a) A dipole of moment 4 × 10⁻⁹ C m makes 30° with a uniform field of 5 × 10⁴ N C⁻¹. Find the torque on it. (b) Charges of ±2 μC are 1 cm apart. Find the largest torque on this dipole in a field of 1 × 10⁵ N C⁻¹.
- (a) τ = pE sin θ = 4 × 10⁻⁹ × 5 × 10⁴ × sin 30°.
- τ = 2 × 10⁻⁴ × 0.5 = 1 × 10⁻⁴ N m.
- (b) p = q × 2a = 2 × 10⁻⁶ C × 0.01 m = 2 × 10⁻⁸ C m.
- The torque is largest at θ = 90°: τ(max) = pE = 2 × 10⁻⁸ × 1 × 10⁵ = 2 × 10⁻³ N m.
(a) 1 × 10⁻⁴ N m; (b) 2 × 10⁻³ N m
In the LCD screen of a calculator or TV, a small electric field turns rod-shaped molecules that behave like dipoles. Turning them changes how light passes through, which forms the digits and pictures. A comb rubbed in dry hair lifting paper bits uses the same pull on dipoles.
3 marks: “Derive an expression for the torque on an electric dipole in a uniform electric field. Write it in vector form.” The forces qE and −qE form a couple with arm 2a sin θ. τ = qE × 2a sin θ = pE sin θ; vector form τ = p × E.
2 marks: “Show that the net force on a dipole in a uniform field is zero. When is the dipole in stable equilibrium?” The forces +qE and −qE are equal and opposite, so they cancel. Stable equilibrium when p is along E (θ = 0°): the torque is zero and a small turn brings it back.
1 marks: “At what angle between p and E is the torque on a dipole maximum?” At 90°, where τ = pE.
Uniform field: twist, no push (τ = pE sin θ, F = 0). Non-uniform field: twist and push.