Lenses: the lens maker's formula and the thin lens formula
A thin lens is two refracting surfaces. Together they give the lens maker's formula, 1/f = (n₂₁ − 1)(1/R₁ − 1/R₂), and 1/v − 1/u = 1/f.
Lens words and ray rules
A lens is a transparent body bounded by two surfaces, at least one of them curved. A thin lens is much thinner than its radii of curvature, so all distances are measured from its optical centre. In air, a convex lens (thicker in the middle) converges light, and a concave lens (thinner in the middle) diverges it. A lens has two principal foci, one on each side. Three rays help you draw any image. (1) A ray parallel to the axis passes through the far focus (convex lens), or seems to come from the near focus (concave lens). (2) A ray through the optical centre goes on undeviated. (3) A ray through the near focus (convex), or heading for the far focus (concave), leaves parallel to the axis.
Derivation: lens maker's formula and thin lens formula
A thin lens of refractive index n₂ sits in a medium of refractive index n₁. A point object O is on the axis. Use paraxial rays and the formula for one refracting surface, twice.
- 1The first surface (radius R₁) alone would form an image I₁ at distance v₁: n₂/v₁ − n₁/u = (n₂ − n₁)/R₁. ...(1)
- 2I₁ acts as the object for the second surface (radius R₂). Light now goes from n₂ back into n₁. The lens is thin, so I₁ is also at distance v₁ from this surface.
- 3Second surface: n₁/v − n₂/v₁ = (n₁ − n₂)/R₂. ...(2)
- 4Add (1) and (2). The n₂/v₁ terms cancel: n₁/v − n₁/u = (n₂ − n₁)(1/R₁ − 1/R₂).
- 5Divide by n₁ and write n₂₁ = n₂/n₁: 1/v − 1/u = (n₂₁ − 1)(1/R₁ − 1/R₂). ...(3)
- 6For an object at infinity (u = −∞), the image forms at the focus, so v = f.
- 7★So, 1/f = (n₂₁ − 1)(1/R₁ − 1/R₂). This is the lens maker's formula.
- 8★Put this into (3): 1/v − 1/u = 1/f. This is the thin lens formula.
★ key step
How to draw the ray diagram for the derivation
- Draw a principal axis and a thin double convex lens across it. Call its left face the first surface and its right face the second surface.
- Mark the object O on the axis on the left. Mark C₁, the centre of the first surface, on the right, and C₂, the centre of the second surface, on the left.
- Draw a ray from O to the first surface. Bend it towards the axis, and continue it as a dotted line to I₁, where the first surface alone would form the image.
- At the second surface, bend the ray further so that it meets the axis at I, nearer the lens than I₁.
- Label n₁ outside the lens, n₂ inside, and R₁, R₂, u, v₁ and v. Put arrows on the rays.
Signs of R₁, R₂ and f for common lenses in air (n = 1.5)
| Lens | R₁ | R₂ | Focal length |
|---|---|---|---|
| Double convex (equiconvex) | +R | −R | f = +R (converging) |
| Plano-convex (curved face towards the light) | +R | ∞ | f = +2R (converging) |
| Double concave (equiconcave) | −R | +R | f = −R (diverging) |
| Plano-concave (curved face towards the light) | −R | ∞ | f = −2R (diverging) |
Worked example: lens maker's formula
(a) An equiconvex lens of glass (n = 1.5) has radii of curvature of 20 cm. Find its focal length in air. (b) Find its focal length when it is immersed in water (n = 4/3). (c) A plano-convex lens of the same glass has a focal length of 30 cm. Find the radius of curvature of its curved face.
- (a) R₁ = +20 cm, R₂ = −20 cm and n₂₁ = 1.5.
- 1/f = (1.5 − 1)(1/20 + 1/20) = 0.5 × 2/20 = 1/20, so f = +20 cm.
- (b) In water, n₂₁ = 1.5 ÷ (4/3) = 9/8.
- 1/f = (9/8 − 1)(2/20) = (1/8)(1/10) = 1/80, so f = +80 cm: four times longer, and still converging.
- (c) R₂ = ∞, so 1/f = (1.5 − 1)(1/R₁) = 1/(2R₁). Then f = 2R₁, so R₁ = 30 cm ÷ 2 = 15 cm.
(a) +20 cm. (b) +80 cm. (c) 15 cm
Activity: focal length of a convex lens and of a concave lens
Two practical experiments on an optical bench, using the no-parallax method.
- 1Convex lens (u-v method): Mount the lens on the optical bench. Place the object needle beyond F. Locate the real, inverted image with the image needle by removing parallax.
- 2Record u (negative) and v (positive) for six object positions. Find f = uv/(u − v) for each, and take the mean.
- 3Graphs: v against u is a curve (a rectangular hyperbola). With signs, 1/v against 1/u is a straight line of slope 1 that cuts the 1/v axis at 1/f. If you plot sizes without signs, the line cuts both axes at 1/f.
- 4Result: f is positive. For example, u = −30 cm and v = +60 cm give f = (−1800) ÷ (−90) = +20 cm.
- 5Concave lens (using a convex lens): Form a real image I of the needle with the convex lens alone, and mark its position.
- 6Place the concave lens between the convex lens and I. The image moves farther away, to I′. Locate I′ by removing parallax.
- 7For the concave lens, I is a virtual object: u = +(distance to I) and v = +(distance to I′). Use f = uv/(u − v).
- 8Result: f is negative. For example, u = +10 cm and v = +15 cm give f = 150 ÷ (−5) = −30 cm.
Spectacle makers grind lenses to the power a doctor prescribes. They choose the glass (n) and the curvature of each face (R₁ and R₂), exactly as the lens maker's formula says.
5 marks: “Derive the lens maker's formula for a thin double convex lens. Hence obtain the thin lens formula. State the assumptions you make.” Assumptions: thin lens, paraxial rays, point object. Ray diagram. First surface: n₂/v₁ − n₁/u = (n₂ − n₁)/R₁. Second surface: n₁/v − n₂/v₁ = (n₁ − n₂)/R₂. Add and divide by n₁. Put u = −∞, v = f: 1/f = (n₂₁ − 1)(1/R₁ − 1/R₂). Hence 1/v − 1/u = 1/f.
3 marks: “A convex lens of glass (n = 1.5) has a focal length of 20 cm in air. Find its focal length in water (n = 4/3). Does it still converge light?” In air: (1.5 − 1)(1/R₁ − 1/R₂) = 1/20, so (1/R₁ − 1/R₂) = 1/10. In water: 1/f = (9/8 − 1) × 1/10 = 1/80, so f = 80 cm. It still converges, because n(glass) > n(water).
2 marks: “A glass lens (n = 1.5) is placed in a liquid of refractive index 1.6. How does its behaviour change? Explain.” n₂₁ = 1.5/1.6 is less than 1, so (n₂₁ − 1) is negative and f changes sign. A convex lens now diverges light, and a concave lens converges it.
The lens maker needs n, R₁ and R₂; the thin lens formula needs u, v and f.