Dielectrics and electric polarisation
A dielectric has no free charges. In a field its molecules become lined-up dipoles, and the surface charges they create reduce the field inside to E₀/K.
Non-polar vs polar molecules
Either way, a dielectric in a field gains a net dipole moment along the field. This is polarisation.
How a dielectric slab reduces the field
Place a dielectric slab in a uniform external field E₀, at right angles to its faces.
- 1Each molecule becomes a dipole lined up with E₀ (induced, or turned into line).
- 2Inside the slab, the + end of one dipole sits next to the − end of the next, so there is no net charge in the bulk.
- 3At the faces, the ends are left uncovered: negative charge on the face where the field enters, positive charge on the face where it leaves.
- 4These surface charges make a field opposite to E₀ inside the slab.
- 5★So the net field inside is reduced: E = E₀/K. It is not zero, because bound charges can shift only a little.
★ key step
Conductor vs dielectric in an external field
Dielectric constants (approximate)
| Material | K |
|---|---|
| Vacuum | 1 (exactly) |
| Air | about 1.0006, taken as 1 |
| Glass | about 5 to 10 |
| Mica | about 6 |
| Water | about 80 |
Polarisation and permittivity
Polarisation P is the dipole moment per unit volume, so its unit is C m⁻². For most materials (linear and isotropic), P is proportional to the field: P = ε₀χₑE. The constant χₑ, which has no unit, is the electric susceptibility. The permittivity of the medium is ε = ε₀K, so the dielectric constant is K = ε/ε₀. Because a dielectric weakens fields, it weakens the Coulomb force between charges K times. It also raises the capacitance of a capacitor K times. Extra help, beyond your textbook: K = 1 + χₑ.
Worked example: field inside a slab
A uniform field of 6 × 10⁴ N C⁻¹ acts at right angles to a glass slab of dielectric constant 6. Find (a) the field inside the slab and (b) the potential difference across the slab if it is 5 mm thick.
- (a) E = E₀/K = 6 × 10⁴ ÷ 6 = 1 × 10⁴ N C⁻¹.
- (b) The field inside is uniform, so V = Ed = 1 × 10⁴ N C⁻¹ × 5 × 10⁻³ m = 50 V.
(a) 1 × 10⁴ N C⁻¹; (b) 50 V
Water's dielectric constant is about 80, so it weakens the pull between Na⁺ and Cl⁻ ions about 80 times. That is why salt dissolves easily in water for your sambar, but not in cooking oil, whose dielectric constant is small.
2 marks: “Distinguish between polar and non-polar molecules, giving one example of each.” Polar: centres of + and − charge separated, so a permanent dipole (H₂O). Non-polar: centres coincide, so no permanent dipole (O₂). Both get polarised in a field.
3 marks: “Explain, with a labelled diagram, how a dielectric slab placed in a uniform field reduces the field inside it. Define dielectric constant.” Molecules line up as dipoles; charges cancel in the bulk; −σₚ and +σₚ appear on the faces; their field opposes E₀, so E = E₀/K. K = ε/ε₀ = E₀/E.
1 marks: “What is the dielectric constant of a metal?” Effectively infinite, because the field inside a conductor is zero.
Polar = permanent dipole (water); non-polar = no dipole until a field acts (oxygen). A dielectric divides the field by K.