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Unit XII · Atoms
9 min readConcept sheet1-mark MCQ, 2-mark statement of a postulate or de Broglie's explanation of it, 3-mark postulates with limitations; also a NEET favourite

Bohr's model of the hydrogen atom: the three postulates

Bohr kept the nucleus but added quantum rules: electrons move in stationary orbits without radiating, with angular momentum nh/2π, and emit a photon only when jumping between orbits.

Postulate 1The electron revolves only in certain stable orbits (stationary states) without radiating energy
Postulate 2 (quantum condition)Angular momentum L = mvr = nh/2π, with n = 1, 2, 3, ... (principal quantum number)
Postulate 3 (frequency condition)hν = E(initial) − E(final) when the electron jumps from a higher orbit to a lower one
Planck's constanth = 6.63 × 10⁻³⁴ J s; h/2π = 1.06 × 10⁻³⁴ J s

Bohr's three postulates (1913)

  • Stationary orbits: an electron can revolve only in certain fixed orbits. In these orbits it does not radiate energy, even though it is accelerating. Each orbit has a fixed energy, so these are called stationary states.
  • Quantum condition: the allowed orbits are those in which the angular momentum of the electron is a whole-number multiple of h/2π: mvr = nh/2π, n = 1, 2, 3, ...
  • Frequency condition: an electron can jump from an orbit of higher energy to one of lower energy. It then emits a photon whose energy equals the energy difference: hν = E(initial) − E(final). It absorbs a photon of the same energy to jump up.

How the postulates fix Rutherford's problems

Niels Bohr, a Danish physicist, mixed classical mechanics with Planck's quantum idea. Postulate 1 simply declares the allowed orbits stable, so the atom does not collapse. Postulate 2 picks out only some orbits, so the electron can have only certain energies. Postulate 3 then means only certain photon energies can come out. Fixed photon energies mean fixed wavelengths, so the atom gives a line spectrum, as seen in experiments.

de Broglie's explanation of the second postulate

Bohr gave no reason why angular momentum should come only in steps of h/2π. In 1923, Louis de Broglie explained it with the wave nature of the electron.

  1. 1
    An electron moving with momentum mv has a de Broglie wavelength λ = h/(mv).
  2. 2
    In a stable orbit, the electron wave must join up with itself all round the circle and form a standing wave, like the waves on a plucked string.
  3. 3
    So a whole number of wavelengths must fit into the circumference of the nth orbit: 2πrₙ = nλ, n = 1, 2, 3, ...
    To draw: a circle with a wave running round it that joins smoothly; for n = 4, four whole waves fit.
  4. 4
    Put λ = h/(mvₙ): 2πrₙ = nh/(mvₙ).
  5. 5
    Rearrange: mvₙrₙ = nh/2π. So, Bohr's quantum condition follows from the wave nature of the electron: only orbits that hold whole standing waves can exist.

Worked example: angular momentum in an orbit

Problem

Find the angular momentum of an electron in the third orbit (n = 3) of hydrogen. By how much does it change when the electron jumps to n = 2? (h = 6.63 × 10⁻³⁴ J s, π = 3.14)

Working
  1. Formula: L = nh/2π.
  2. h/2π = 6.63 × 10⁻³⁴ ÷ 6.28 = 1.056 × 10⁻³⁴ J s.
  3. L₃ = 3 × 1.056 × 10⁻³⁴ = 3.17 × 10⁻³⁴ J s.
  4. Change from n = 3 to n = 2: ΔL = (3 − 2) × h/2π = 1.06 × 10⁻³⁴ J s, a decrease.
Answer

L₃ ≈ 3.17 × 10⁻³⁴ J s; it decreases by 1.06 × 10⁻³⁴ J s

Worked example: frequency of the emitted photon

Problem

An electron in a hydrogen atom jumps from an orbit of energy −1.51 eV to an orbit of energy −3.40 eV. Find the energy and frequency of the photon emitted. (h = 6.63 × 10⁻³⁴ J s, 1 eV = 1.6 × 10⁻¹⁹ J)

Working
  1. Formula: hν = E(initial) − E(final).
  2. Photon energy = −1.51 eV − (−3.40 eV) = 1.89 eV.
  3. In joules: 1.89 × 1.6 × 10⁻¹⁹ = 3.02 × 10⁻¹⁹ J.
  4. ν = 3.02 × 10⁻¹⁹ J ÷ 6.63 × 10⁻³⁴ J s = 4.56 × 10¹⁴ Hz.
Answer

Photon energy 1.89 eV; frequency ≈ 4.56 × 10¹⁴ Hz (red light)

Limitations of Bohr's model

  • It works only for hydrogen-like (hydrogenic) atoms, which have a single electron: H, He⁺, Li²⁺. It fails even for helium, which has two electrons, because it cannot handle the forces between electrons.
  • It gives the frequencies of the spectral lines correctly but cannot explain their relative intensities (why some lines are brighter than others).
In real life

The colours of Diwali fireworks come from metal salts: strontium gives red, barium green, sodium yellow. Each colour is a photon given out when electrons jump between fixed energy levels, just as Bohr's third postulate says.

Exam angle

2 marks: “Using de Broglie's hypothesis, explain Bohr's second postulate of the quantisation of angular momentum.” The orbiting electron behaves as a standing wave, so a whole number of de Broglie wavelengths fit in its orbit: 2πr = nλ. With λ = h/mv, this gives mvr = nh/2π.

3 marks: “State the three postulates of Bohr's model of the hydrogen atom.” (1) Electron moves in certain stationary orbits without radiating. (2) Allowed orbits have mvr = nh/2π. (3) A jump between orbits emits or absorbs a photon with hν = E(initial) − E(final).

2 marks: “Give two limitations of Bohr's model of the atom.” It applies only to one-electron (hydrogen-like) atoms. It cannot explain the relative intensities of spectral lines.

Remember it

Orbit, Quantise, Jump: stable Orbits, Quantised L = nh/2π, a Jump gives hν = E(initial) − E(final).