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Unit IX · Ray optics and optical instruments
12 min readPathway sheetA 5-mark labelled ray diagram of a refracting or reflecting telescope with its magnifying power, 1-mark assertion-reason and 2-mark advantages of a reflecting telescope; also a NEET favourite

Astronomical telescopes: refracting and reflecting

A refracting telescope pairs a long-focus objective with a short-focus eyepiece: m = fₒ/fₑ in normal adjustment. A reflecting telescope uses a concave mirror instead.

Magnifying power (normal adjustment)m = fₒ/fₑ, with the final image at infinity. Tube length L = fₒ + fₑ
Final image at the near pointm = (fₒ/fₑ)(1 + fₑ/D), and the tube is a little shorter than fₒ + fₑ. Your textbook derives only normal adjustment, but uses this case in its exercises
Reflecting telescopeThe objective is a concave mirror with fₒ = R/2, and m = fₒ/fₑ. A Cassegrain design adds a small convex secondary mirror, which gives a longer effective focal length in a short tube
Light-gathering powerDepends on the area of the objective, so it grows with the square of its diameter

The refracting telescope

A telescope gives an angular magnification of distant objects. An astronomical refracting telescope has an objective of long focal length and large aperture, and an eyepiece of short focal length. Light from a distant star forms a real, inverted image in the focal plane of the objective. The eyepiece magnifies this image. In normal adjustment, the image lies at the focus of the eyepiece, so the final image is at infinity and the eye is relaxed. The magnifying power is m = β/α. Here α is the angle the object subtends at the objective, and β is the angle the final image subtends at the eye. The final image is inverted, which does not matter for stars. A terrestrial telescope adds a pair of inverting lenses to give an erect image.

Derivation: magnifying power of a refracting telescope

  1. 1
    A distant object subtends a small angle α at the objective. The telescope is tiny compared with this distance, so α is also the angle at the unaided eye.
  2. 2
    The objective forms an image of height h in its focal plane: α ≈ tan α = h/fₒ.
  3. 3
    In normal adjustment this image lies at the focus of the eyepiece. The final image at infinity subtends β ≈ tan β = h/fₑ.
  4. 4★
    Magnifying power m = β/α = (h/fₑ) ÷ (h/fₒ) = fₒ/fₑ.
  5. 5
    The distance between the two lenses is the tube length, L = fₒ + fₑ.
  6. 6
    If the final image is at the near point, the eyepiece works as a simple microscope, and m = (fₒ/fₑ)(1 + fₑ/D). (Your textbook does not derive this case, but its exercises use it.)
  7. 7
    So a large m needs a long fₒ and a short fₑ.

★ key step

How to draw: refracting telescope in normal adjustment

  1. 1
    Draw a horizontal axis. Draw a large convex lens on the left (objective) and a small convex lens on the right (eyepiece).
  2. 2
    Keep them fₒ + fₑ apart. Mark a point F between them, fₒ from the objective and fₑ from the eyepiece: the two foci coincide here.
  3. 3
    From the far left, draw three parallel rays from the top of a distant object, sloping down at a small angle α to the axis.
  4. 4
    Draw the middle ray through the centre of the objective, undeviated. Bend the other two so that all three meet at one point below F, in the focal plane.
  5. 5
    Draw the real, inverted image as a short arrow from F down to this point.
  6. 6
    Continue the rays to the eyepiece. Draw the ray from the image tip through the centre of the eyepiece undeviated, and bend the others so they leave parallel to it.
  7. 7
    Draw an eye on the right. Mark α at the objective and β at the eye, and write 'final image at infinity'.
  8. 8
    Label objective, eyepiece, fₒ, fₑ, F and the image, and put arrows on all rays.

How to draw: Cassegrain reflecting telescope

  1. 1
    Draw a large concave mirror on the right, facing left, with a small hole at its centre on the axis. This is the primary mirror (the objective).
  2. 2
    Draw parallel rays from a distant object coming from the left and striking the primary mirror.
  3. 3
    Reflect them towards the primary's focus. Before they reach it, draw a small convex mirror on the axis, facing the primary. This is the secondary mirror.
  4. 4
    Reflect the rays from the secondary mirror back towards the primary, so that they pass through the hole.
  5. 5
    Show the rays meeting at an image just behind the hole. Draw the eyepiece behind this image, and an eye beyond it.
  6. 6
    Label: primary concave mirror (objective), secondary convex mirror, hole, eyepiece, eye, and light from a distant star.

Refracting versus reflecting telescope

Refracting (lens objective)Large lenses are heavy and hard to make free of flaws. They can be held only at the rim, so they sag under their own weight. A lens suffers chromatic aberration (colour fringes) and spherical aberration.
Reflecting (mirror objective)No chromatic aberration: a mirror reflects all colours alike. A paraboloidal mirror removes spherical aberration. A mirror is lighter and can be supported over its whole back, so very large apertures are possible, gathering more light.

One drawback of a reflecting telescope: the secondary mirror blocks a little of the incoming light.

Worked example: telescopes

Problem

(a) A refracting telescope has fₒ = 100 cm and fₑ = 5 cm. Find its magnifying power and tube length in normal adjustment. (b) Find its magnifying power when the final image is at the near point (D = 25 cm). (c) A reflecting telescope uses a concave mirror of radius of curvature 4.0 m as its objective. Its eyepiece, of focal length 2.0 cm, views the image this mirror forms. Find its magnifying power.

Working
  1. (a) m = fₒ/fₑ = 100/5 = 20. Tube length L = fₒ + fₑ = 100 cm + 5 cm = 105 cm.
  2. (b) m = (fₒ/fₑ)(1 + fₑ/D) = 20 × (1 + 5/25) = 20 × 1.2 = 24.
  3. (c) fₒ = R/2 = 4.0 m ÷ 2 = 2.0 m = 200 cm.
  4. m = fₒ/fₑ = 200 cm ÷ 2.0 cm = 100.
Answer

(a) m = 20, L = 105 cm. (b) m = 24. (c) m = 100

In real life

The Vainu Bappu Telescope at Kavalur in Tamil Nadu and the Devasthal telescope near Nainital are both reflecting telescopes. Indian astronomers use them to study stars and galaxies.

Exam angle

5 marks: “Draw a labelled ray diagram of an astronomical refracting telescope in normal adjustment and derive its magnifying power. Write two advantages of a reflecting telescope.” Diagram as in 'How to draw'. α = h/fₒ and β = h/fₑ, so m = β/α = fₒ/fₑ, with L = fₒ + fₑ. Reflecting telescope: no chromatic aberration; a paraboloidal mirror removes spherical aberration; lighter, supported over its whole back.

3 marks: “Draw a labelled ray diagram of a Cassegrain reflecting telescope. Write the expression for the magnifying power of a reflecting telescope.” Concave primary mirror with a central hole, convex secondary mirror, eyepiece behind the hole, rays from a distant star. m = fₒ/fₑ. For a single concave mirror objective, fₒ = R/2; the convex secondary makes the effective fₒ longer.

2 marks: “An astronomical telescope has lenses of power 0.5 D and 20 D. Which lens is the objective? Find the magnifying power in normal adjustment.” The 0.5 D lens (fₒ = 2 m = 200 cm) is the objective, because it has the longer focal length. fₑ = 1/20 m = 5 cm. m = 200/5 = 40.

Remember it

Telescope: objective long, eyepiece short. m = fₒ/fₑ, and the tube is fₒ + fₑ long.