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Unit XVIII · Genetics
9 min readPathway sheetPart II (2 marks) on the laws; Part IV (7 marks) with a 16-box checkerboard

Mendel's dihybrid cross and the laws of inheritance

Crossing round yellow and wrinkled green peas gives all round yellow F₁. The F₂ shows 9 : 3 : 3 : 1, proving the law of independent assortment.

Dihybrid crossParents differ in two pairs of contrasting characters
F₂ phenotypic ratio9 round yellow : 3 round green : 3 wrinkled yellow : 1 wrinkled green
Gametes of F₁ (RrYy)RY, Ry, rY and ry, in equal numbers
New combinationsRound green and wrinkled yellow appear in the F₂

The cross, step by step

  1. 1
    Parents: round yellow RRYY × wrinkled green rryy.
  2. 2
    Gametes: RY from the first parent and ry from the second.
  3. 3★
    F₁: all RrYy, all round yellow (round and yellow are dominant).
  4. 4
    F₁ plants are self-pollinated: RrYy × RrYy.
  5. 5
    Each F₁ plant makes four kinds of gametes: RY, Ry, rY and ry, in equal numbers.
  6. 6
    These combine in a 4 × 4 checkerboard, giving 16 combinations.
  7. 7★
    F₂: 9 round yellow : 3 round green : 3 wrinkled yellow : 1 wrinkled green.

★ key step

Checkerboard for the F₂ (RrYy × RrYy)

Female gametes ↓ / Male gametes →RYRyrYry
RYRRYYRRYyRrYYRrYy
RyRRYyRRyyRrYyRryy
rYRrYYRrYyrrYYrrYy
ryRrYyRryyrrYyrryy

Counting the 16 boxes

Round yellow9 (RRYY 1, RRYy 2, RrYY 2, RrYy 4)
Round green3 (RRyy 1, Rryy 2)
Wrinkled yellow3 (rrYY 1, rrYy 2)
Wrinkled green1 (rryy)
Total16

Mendel's laws of inheritance

  • Law of dominance: in a hybrid, one allele (dominant) shows and the other (recessive) is hidden.
  • Law of segregation (purity of gametes): the two alleles of a gene separate during gamete formation, so each gamete gets only one.
  • Law of independent assortment: alleles of different characters go into gametes independently of each other. Seed shape does not decide seed colour.
  • Proof: new combinations, round green and wrinkled yellow, appear in the F₂.
  • Each character on its own still gives 3 : 1: 12 round : 4 wrinkled, and 12 yellow : 4 green.

Using the 9 : 3 : 3 : 1 ratio

Problem

A dihybrid F₂ has 320 pea plants. How many are expected to be round green?

Working
  1. Ratio = 9 : 3 : 3 : 1, so there are 16 parts in all.
  2. Round green = 3 parts out of 16.
  3. Number = 320 × 3/16.
  4. 320 ÷ 16 = 20, and 20 × 3 = 60.
  5. Check the whole set: round yellow 180, round green 60, wrinkled yellow 60, wrinkled green 20; total 320.
Answer

About 60 round green plants.

In real life

Rice breeders combine high yield from one parent with disease resistance from another to make a new variety. Independent assortment is what makes such new combinations possible.

Exam angle

1 marks: “How many kinds of gametes does an RrYy plant make?” Four: RY, Ry, rY and ry.

2 marks: “State the law of independent assortment.” When two pairs of characters are inherited, the alleles of each pair go into gametes independently of the other pair.

7 marks: “Explain Mendel's dihybrid cross with a checkerboard.” P: RRYY × rryy; F₁ RrYy, round yellow; four kinds of gametes; 16-box checkerboard; F₂ 9 : 3 : 3 : 1; new combinations prove independent assortment.

Remember it

Di means two traits: 16 boxes, 9 : 3 : 3 : 1. The two 3's are the new mixes.