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Unit VI · Nuclear physics
7 min readConcept sheetPart II (2 marks) the law; Part III (4 marks) completing decay equations

Soddy and Fajans' radioactive displacement law

In alpha decay, mass number falls by 4 and atomic number by 2. In beta decay, mass number stays the same and atomic number rises by 1.

Alpha decayA decreases by 4; Z decreases by 2
Beta decayA unchanged; Z increases by 1
Gamma decayNo change in A or Z
Given byFrederick Soddy and Kasimir Fajans, 1913

The law and the symbols

A nucleus is written with two numbers. In ₉₂U²³⁸, the number at the bottom left is the atomic number Z = 92 (the number of protons). The number at the top right is the mass number A = 238 (protons + neutrons). In 1913, Frederick Soddy and Kasimir Fajans gave the radioactive displacement law. It tells how Z and A change when a nucleus gives out radiation. The original nucleus is the parent nucleus; the new one formed is the daughter nucleus. The daughter is a new element, so it is displaced (moved) in the periodic table.

The three rules

  1. α★
    Alpha decay: parent (Z, A) → daughter (Z − 2, A − 4) + ₂He⁴
    Example: ₉₂U²³⁸ → ₉₀Th²³⁴ + ₂He⁴. The daughter moves two places back in the periodic table.
  2. β★
    Beta decay: parent (Z, A) → daughter (Z + 1, A) + ₋₁e⁰
    Example: ₉₀Th²³⁴ → ₉₁Pa²³⁴ + ₋₁e⁰. A neutron in the nucleus changes into a proton and an electron, and the electron is thrown out. The daughter moves one place forward.
  3. γ
    Gamma decay: excited nucleus (Z, A) → same nucleus (Z, A) + γ
    Only energy is given out, so A and Z do not change. It usually follows an alpha or beta decay.

★ key step

Quick check: what changes

DecayMass number AAtomic number ZPosition in the periodic table
Alpha (α)Decreases by 4Decreases by 22 places to the left
Beta (β)No changeIncreases by 11 place to the right
Gamma (γ)No changeNo changeSame place

Worked example: completing decay equations

Problem

(a) Radium-226 (₈₈Ra²²⁶) gives out an alpha particle. Write the daughter nucleus. (b) Carbon-14 (₆C¹⁴) gives out a beta particle. Write the daughter. (c) ₉₂U²³⁸ finally becomes stable lead, ₈₂Pb²⁰⁶. How many alpha and beta particles are given out?

Working
  1. (a) Alpha: A − 4 = 226 − 4 = 222; Z − 2 = 88 − 2 = 86. Element 86 is radon.
  2. ₈₈Ra²²⁶ → ₈₆Rn²²² + ₂He⁴. Check: 226 = 222 + 4 and 88 = 86 + 2.
  3. (b) Beta: A stays 14; Z + 1 = 6 + 1 = 7. Element 7 is nitrogen.
  4. ₆C¹⁴ → ₇N¹⁴ + ₋₁e⁰. Check: 14 = 14 + 0 and 6 = 7 + (−1).
  5. (c) Only alpha decay changes A. The fall in A = 238 − 206 = 32, so the number of alphas = 32 ÷ 4 = 8.
  6. 8 alphas lower Z by 8 × 2 = 16, giving 92 − 16 = 76. But lead has Z = 82.
  7. Each beta raises Z by 1, so the number of betas = 82 − 76 = 6.
Answer

(a) ₈₆Rn²²² (b) ₇N¹⁴ (c) 8 alpha and 6 beta particles

In real life

Carbon-14 in every living thing slowly turns into nitrogen-14 by beta decay. Scientists use this to find the age of ancient objects, such as charcoal from the Keeladi excavation near Madurai.

Exam angle

2 marks: “State Soddy and Fajans' displacement law for alpha decay.” When a nucleus emits an alpha particle, its mass number decreases by 4 and its atomic number by 2: ₉₂U²³⁸ → ₉₀Th²³⁴ + ₂He⁴.

2 marks: “Why does beta decay raise the atomic number but not the mass number?” A neutron turns into a proton and an electron, and the electron leaves. Protons rise by 1, but the total number of protons and neutrons stays the same.

4 marks: “₉₀Th²³² emits one alpha particle and then two beta particles. Find the final nucleus.” After α: A = 228, Z = 88. After two β: A = 228, Z = 90. Final nucleus: ₉₀Th²²⁸, an isotope of the parent.

Remember it

α: A minus 4, Z minus 2 (two steps back). β: same A, Z plus 1 (one step forward). γ: no change.