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Unit VII · Atoms and molecules
8 min readConcept sheetPart I (1 mark) and Part II (2 marks); an average atomic mass sum can come in Part III (4 marks)

Atomic mass, relative atomic mass and average atomic mass

Atoms are too light to weigh, so we compare them with 1/12 of a carbon-12 atom. Most elements are isotope mixtures, so we use an average atomic mass.

1 atomic mass unit (amu or u)1/12 of the mass of one carbon-12 atom = 1.66 × 10⁻²⁴ g
Relative atomic mass (RAM)Average mass of one atom ÷ (1/12 × mass of one C-12 atom). It has no unit.
Average atomic massSum of (mass of each isotope × its percentage) ÷ 100
ChlorineCl-35 (75.77%) and Cl-37 (24.23%) give an average of 35.48 u

Why we need a reference atom

One hydrogen atom weighs only about 1.67 × 10⁻²⁴ g. No balance can weigh something so light. So scientists compare every atom with one standard atom. Since 1961 the standard is carbon-12 (C-12). One atomic mass unit (amu) is 1/12 of the mass of one C-12 atom. Today it is also called the unified atomic mass unit, with the symbol u.

Relative atomic mass in simple words

  • Relative atomic mass (RAM) tells how many times one atom is heavier than 1/12 of a C-12 atom.
  • RAM = average mass of one atom of the element ÷ (1/12 × mass of one C-12 atom).
  • It is a ratio of two masses, so it has no unit. When we write it with u, we call it the atomic mass.
  • Common values: H = 1, C = 12, N = 14, O = 16, Na = 23, Mg = 24, S = 32, Cl = 35.5, Ca = 40.
  • Many values are not whole numbers because natural elements are mixtures of isotopes (atoms of one element with different masses).

Worked example: average atomic mass of chlorine

Problem

Chlorine has two isotopes: Cl-35 (abundance 75.77%) and Cl-37 (abundance 24.23%). Find the average atomic mass of chlorine.

Working
  1. Formula: average atomic mass = (A₁ × p₁ + A₂ × p₂) ÷ 100, where A is the mass of an isotope and p is its percentage.
  2. Cl-35 part: 35 × 75.77 = 2651.95
  3. Cl-37 part: 37 × 24.23 = 896.51
  4. Add: 2651.95 + 896.51 = 3548.46
  5. Divide by 100: 3548.46 ÷ 100 = 35.48 (rounded to two decimal places)
Answer

Average atomic mass of chlorine = 35.48 u. Tables round it to 35.5.

Worked example: average atomic mass of magnesium

Problem

Natural magnesium has three isotopes: Mg-24 (79%), Mg-25 (10%) and Mg-26 (11%). Find its average atomic mass.

Working
  1. Formula: average atomic mass = (A₁ × p₁ + A₂ × p₂ + A₃ × p₃) ÷ 100
  2. Mg-24 part: 24 × 79 = 1896
  3. Mg-25 part: 25 × 10 = 250
  4. Mg-26 part: 26 × 11 = 286
  5. Add: 1896 + 250 + 286 = 2432
  6. Divide by 100: 2432 ÷ 100 = 24.32
Answer

Average atomic mass of magnesium = 24.32 u. Tables round it to 24.3.

In real life

Salt makers in India add potassium iodate (KIO₃) to make iodised salt. They use atomic masses (K = 39, I = 127, O = 16) to work out how much to mix into each tonne of salt.

Exam angle

1 marks: “The reference atom used for atomic masses today is: (a) H-1 (b) O-16 (c) C-12 (d) N-14” (c) C-12. One amu is 1/12 of the mass of one C-12 atom.

2 marks: “What is relative atomic mass? Why is it written without a unit?” RAM = average mass of one atom of the element ÷ (1/12 × mass of one C-12 atom). It is a ratio of two masses, so the units cancel.

4 marks: “Lithium has two isotopes, Li-6 (7.5%) and Li-7 (92.5%). Calculate the average atomic mass of lithium.” Write the formula. (6 × 7.5 + 7 × 92.5) ÷ 100 = (45 + 647.5) ÷ 100 = 692.5 ÷ 100 = 6.925 u.

Remember it

One-twelfth of carbon-twelve is the ruler for every atom.