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Unit VII · Atoms and molecules
6 min readConcept sheetPart I (1 mark) and Part II (2 marks: find the RMM of a compound); part of a 4-mark sum

Relative molecular mass

Relative molecular mass is the sum of the relative atomic masses of all atoms in a molecule. Like atomic mass, it has no unit.

DefinitionRMM = mass of one molecule ÷ (1/12 × mass of one C-12 atom)
Quick methodRMM = sum of (number of each atom × its RAM)
Water, H₂O2(1) + 16 = 18
Sulphuric acid, H₂SO₄2(1) + 32 + 4(16) = 98

What it means

A molecule is two or more atoms joined together. Its relative molecular mass (RMM) tells how many times one molecule is heavier than 1/12 of a C-12 atom. In practice we simply add the relative atomic masses of all its atoms. For ionic compounds such as NaCl, the same sum is often called the formula mass.

How to find RMM in four steps

  1. 1
    Write the correct molecular formula, for example H₂SO₄.
  2. 2
    List each element and count its atoms: H = 2, S = 1, O = 4.
  3. 3
    Multiply each count by the element's relative atomic mass: 2 × 1, 1 × 32, 4 × 16.
  4. 4
    Add the products: 2 + 32 + 64 = 98. Write no unit (or g mol⁻¹ if the question asks for molar mass).

Worked example: glucose

Problem

Find the relative molecular mass of glucose, C₆H₁₂O₆ (C = 12, H = 1, O = 16).

Working
  1. Carbon: 6 × 12 = 72
  2. Hydrogen: 12 × 1 = 12
  3. Oxygen: 6 × 16 = 96
  4. Add: 72 + 12 + 96 = 180
Answer

RMM of glucose = 180.

Ready reckoner (H = 1, C = 12, N = 14, O = 16, Na = 23, Ca = 40, Cl = 35.5)

SubstanceFormulaWorkingRMM
WaterH₂O2(1) + 1618
AmmoniaNH₃14 + 3(1)17
Carbon dioxideCO₂12 + 2(16)44
EthanolC₂H₅OH2(12) + 6(1) + 1646
Common saltNaCl23 + 35.558.5
UreaCO(NH₂)₂12 + 16 + 2(14) + 4(1)60
Calcium carbonateCaCO₃40 + 12 + 3(16)100
In real life

ORS (oral rehydration salts) recipes give the glucose and salt in moles per litre. Makers turn these into grams using molecular masses such as glucose = 180 and NaCl = 58.5.

Exam angle

2 marks: “Calculate the relative molecular mass of nitric acid, HNO₃ (H = 1, N = 14, O = 16).” 1 + 14 + 3(16) = 1 + 14 + 48 = 63.

4 marks: “Define relative molecular mass. Calculate the RMM of glucose (C₆H₁₂O₆) and calcium carbonate (CaCO₃).” Definition with C-12. Glucose: 72 + 12 + 96 = 180. CaCO₃: 40 + 12 + 48 = 100.

Remember it

Count, multiply, add: count each atom, multiply by its atomic mass, add them all.