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Unit II · Optics
10 min readConcept sheetPart III (4 marks) or Part IV (7 marks) for myopia and hypermetropia with diagrams; parts of the eye come as 1-mark MCQs

The human eye: defects of vision and their correction

The eye lens changes its focal length to see near and far objects. Myopia is corrected with a concave lens and hypermetropia with a convex lens.

Power of accommodationThe eye lens changes its focal length, using the ciliary muscles, to focus near and far objects
Near point of a normal eye25 cm, the least distance of distinct vision (D)
Far point of a normal eyeInfinity
CorrectionsMyopia: concave; hypermetropia: convex; presbyopia: bifocal; astigmatism: cylindrical

Parts of the eye

PartWhat it does
CorneaClear, curved front window of the eye; light enters through it
IrisColoured ring of muscle; controls the size of the pupil
PupilHole in the centre of the iris; becomes small in bright light and large in dim light
Eye lensConvex lens of clear, jelly-like material; focuses light on the retina
Ciliary musclesChange the thickness of the lens, and so its focal length
RetinaLight-sensitive screen at the back; a real, inverted image forms here
Optic nerveCarries signals from the retina to the brain, which sees the image erect

Power of accommodation

The ciliary muscles can make the eye lens thinner or thicker. This changes its focal length. For a far object, the muscles relax and the lens becomes thin (longer focal length). For a near object, they contract and the lens becomes thick (shorter focal length). This ability is the power of accommodation. A normal eye sees clearly from the near point, 25 cm, to the far point, infinity. The near point distance is called the least distance of distinct vision.

Defects of vision

DefectCannot see clearlyCauseImage formsCorrection
Myopia (short sight)Far objectsEyeball too long, or focal length of the lens too shortIn front of the retinaConcave lens
Hypermetropia (long sight)Near objectsEyeball too short, or focal length of the lens too longBehind the retinaConvex lens
PresbyopiaNear objects, in old ageCiliary muscles become weak and the lens loses flexibilityBehind the retina, for near objectsConvex lens for reading, or a bifocal lens (upper concave part for far vision, lower convex part for reading)
AstigmatismHorizontal and vertical lines at the same timeCornea not perfectly round: it curves differently in different directionsNot sharp in every directionCylindrical lens

How to draw myopia, hypermetropia and their correction

  1. 1
    Draw a circle for the eyeball and a small double-convex lens at its front. Label eye lens and retina (the back of the circle).
  2. 2
    Myopia: draw parallel rays from a distant object entering the eye. Make them meet at a point in front of the retina. Label image.
  3. 3
    Myopia corrected: draw the same eye with a concave lens in front. The rays spread slightly after it and meet on the retina.
  4. 4
    Hypermetropia: draw rays from a near object meeting at a point behind the retina (mark it with dotted lines).
  5. 5
    Hypermetropia corrected: put a convex lens in front of the eye. The rays now meet on the retina.

Lenses for a myopic eye and a hypermetropic eye

Problem

(i) A person with myopia cannot see clearly beyond 2 m. What lens does the person need to see distant objects? Find its focal length and power. (ii) A person with hypermetropia has a near point of 1 m. Find the focal length and power of the lens needed to read a book at 25 cm.

Working
  1. (i) The lens must make a distant object (u = −∞) appear at the far point, 2 m in front of the eye (v = −2 m).
  2. Lens formula: 1/f = 1/v − 1/u = 1/(−2) − 0 = −1/2.
  3. f = −2 m. The negative sign shows a concave lens.
  4. Your textbook's formula gives the same: f = xy/(x − y), where x is the far point and y the distance the person wants to see. For distant objects (y = ∞), f = −x = −2 m.
  5. Power: P = 1/f = 1/(−2) = −0.5 D.
  6. (ii) Your textbook's formula: f = dD/(d − D), where d = 1 m is the near point of the eye and D = 0.25 m.
  7. f = (1 m × 0.25 m) ÷ (1 m − 0.25 m) = 0.25 ÷ 0.75 = 1/3 m ≈ 0.33 m. The positive sign shows a convex lens.
  8. Power: P = 1/f = 1 ÷ (1/3 m) = +3 D.
Answer

(i) A concave lens of focal length 2 m and power −0.5 D. (ii) A convex lens of focal length about 33 cm and power +3 D.

In real life

A student on the last bench who cannot read the blackboard may have myopia, so school eye tests matter. Vitamin A from carrots, papaya and green leafy vegetables keeps the retina healthy and prevents night blindness.

Exam angle

2 marks: “What is the power of accommodation of the eye?” The ability of the eye lens to change its focal length, using the ciliary muscles, to see both near and far objects clearly.

4 marks: “What is myopia? Give its causes and correction, with diagrams.” Far objects look blurred; eyeball too long or focal length too short; image forms in front of the retina; corrected with a concave lens; two ray diagrams.

7 marks: “Explain myopia and hypermetropia with their causes and correction. Draw diagrams.” Myopia: far objects blurred, long eyeball, image in front of retina, concave lens. Hypermetropia: near objects blurred, short eyeball, image behind retina, convex lens. Four labelled diagrams.

Remember it

Myopia: Minus lens (concave). Hypermetropia: plus lens (convex). A short-sighted person sees only short distances clearly.