Kinetic energy and potential energy
Kinetic energy is energy of motion, KE = ½mv². Potential energy is energy of height, PE = mgh. Both are measured in joules.
Kinetic vs potential energy
Activity: a ball or cell rolling down a slope of books
You need two thick books, a hard-bound register to use as a slope, a pencil cell and a heavier torch cell (or a small and a large ball), and an empty matchbox.
- 1Stack two thick books and lean the register on them to make a slope.
- 2Place the matchbox on the table just below the slope.
- 3Let the pencil cell roll down from the top and hit the matchbox. Measure how far the box moves.
- 4Roll the heavier torch cell from the same height. The box moves farther: more mass, more KE.
- 5★Add a book to raise the slope, and roll the pencil cell again. The box moves farther still: more height gives more speed and more KE.
- 6Conclude: as the cell rolls down, its PE changes into KE. KE grows with both mass and speed.
★ key step
How KE and PE change
| Change | Kinetic energy | Potential energy |
|---|---|---|
| Mass doubled | 2 times | 2 times |
| Speed doubled | 4 times | No change |
| Speed made 3 times | 9 times | No change |
| Height doubled | No change | 2 times |
| Height halved | No change | Half |
Worked example: kinetic energy of a scooter
A scooter and its rider have a total mass of 120 kg and move at 10 m s⁻¹. Find their kinetic energy. What is it if the speed doubles?
- KE = ½mv² = ½ × 120 kg × (10 m s⁻¹)².
- KE = 60 × 100 = 6000 J.
- At 20 m s⁻¹: KE = ½ × 120 × 20² = 60 × 400 = 24 000 J.
6000 J (6 kJ). Doubling the speed makes it 24 000 J, four times as much
Worked example: potential energy of a water tank
A rooftop tank holds 500 kg of water at a height of 12 m above the ground. Find the potential energy of the water. (g = 9.8 m s⁻²)
- PE = mgh.
- PE = 500 kg × 9.8 m s⁻² × 12 m.
- PE = 4900 × 12 = 58 800 J.
58 800 J, or about 58.8 kJ
Worked example: speed from kinetic energy
A ball of mass 0.4 kg has 20 J of kinetic energy. Find its speed.
- KE = ½mv², so v² = 2 × KE ÷ m.
- v² = 2 × 20 J ÷ 0.4 kg = 100 m² s⁻².
- v = √100 = 10 m s⁻¹.
10 m s⁻¹
Road safety signs ask drivers to slow down. KE grows with the square of the speed, so a crash at double the speed carries four times the energy. Water stored high in a dam has PE that power stations turn into electricity.
2 marks: “Define kinetic energy and write its formula. How does it change if the speed of a body is tripled?” Kinetic energy is the energy a body has because of its motion: KE = ½mv². Tripling v makes KE 3² = 9 times as large.
2 marks: “Find the potential energy of a 2 kg flower pot on a shelf 3 m high. (g = 9.8 m s⁻²)” PE = mgh = 2 × 9.8 × 3 = 58.8 J.
3 marks: “A 1000 kg car moves at 15 m s⁻¹. Find its kinetic energy. What is its kinetic energy at 30 m s⁻¹, and what does this mean for road safety?” KE = ½ × 1000 × 15² = 112 500 J. At 30 m s⁻¹: KE = ½ × 1000 × 30² = 450 000 J, four times as much. So a crash at double the speed releases four times the energy and does far more damage.
Move it: half m v squared. Lift it: m g h.