haya.Learning made clear
Unit XVII · Carbon and its compounds (lesson 28)
11 min readConcept sheetSection A MCQ (1 mark), often on naming a compound, and true or false (2 marks, two parts); Section B very short answer (2 marks) or short answer (3 marks)

Functional groups and IUPAC names

A functional group gives a compound its typical properties. IUPAC names join a word root for the carbon count with an ending for the group.

Functional groupAn atom or group of atoms that gives a compound its typical properties, such as -OH, -CHO, -COOH or C=C
IUPACInternational Union of Pure and Applied Chemistry; it sets the systematic names of compounds
Word roots1 carbon meth, 2 eth, 3 prop, 4 but, 5 pent, 6 hex, 7 hept, 8 oct
Alkyl groupsChange -ane to -yl: methyl -CH₃, ethyl -C₂H₅, propyl -C₃H₇

Common functional groups

GroupClassName endingExample
C=C (double bond)Alkene-eneEthene, H₂C=CH₂
C≡C (triple bond)Alkyne-yneEthyne, HC≡CH
-X (F, Cl, Br, I)HaloalkanePrefix chloro-, bromo-Chloromethane, CH₃Cl
-OH (hydroxyl)Alcohol-olMethanol, CH₃OH
-CHO (at the end of the chain)Aldehyde-alEthanal, CH₃CHO
C=O inside the chain (keto group)Ketone-onePropanone, CH₃COCH₃
-COOH (carboxyl)Carboxylic acid-oic acidEthanoic acid, CH₃COOH
-COOREster-oateMethyl ethanoate, CH₃COOCH₃

IUPAC rules for alkanes

  1. 1
    Find the longest continuous chain of carbon atoms. Its word root gives the parent name.
    A 6-carbon chain gives hexane
  2. 2
    Name each side group (alkyl group) by changing -ane to -yl.
    -CH₃ is methyl; -C₂H₅ is ethyl
  3. 3
    Number the chain from the end that gives the side groups the lowest numbers.
  4. 4
    Write the number, a hyphen, then the group name joined to the parent name.
    3-ethylhexane: no space between ethyl and hexane
  5. 5
    For different groups, list them in alphabetical order.
    3-ethyl-3-methylhexane
  6. 6★
    For identical groups, use di, tri, tetra. These prefixes are ignored in alphabetical order.
    2,2-dimethylbutane: numbers are separated by a comma

★ key step

Worked example: name these alkanes

Problem

Name: (a) CH₃-CH(CH₃)-CH₂-CH₂-CH₃ (b) CH₃-CH(CH₃)-CH(CH₃)-CH₂-CH₃ (c) CH₃-CH₂-CH(C₂H₅)-CH₂-CH₃

Working
  1. (a) The longest chain has 5 carbons, so the parent is pentane. There is one -CH₃ group.
  2. Numbering from the left puts it on carbon 2; from the right it would be 4. Use the lower number, 2.
  3. (b) The longest chain has 5 carbons. There are two -CH₃ groups, on carbons 2 and 3 from the left (3 and 4 from the right).
  4. Two identical groups take the prefix di, with the numbers 2,3.
  5. (c) The longest chain has 5 carbons, with one -C₂H₅ group on carbon 3 from either end.
Answer

(a) 2-methylpentane (b) 2,3-dimethylpentane (c) 3-ethylpentane

Naming alkenes, alkynes and other groups

  • Alkenes: change -ane to -ene. Give the double bond the lower of its two carbon numbers: CH₂=CH-CH₂-CH₃ is 1-butene; CH₃-CH=CH-CH₃ is 2-butene.
  • Alkynes: change -ane to -yne: HC≡C-CH₃ is propyne; HC≡C-CH₂-CH₃ is 1-butyne.
  • Alcohols: replace the final e of the alkane by -ol: methanol, ethanol, 2-propanol.
  • Aldehydes: replace the e by -al: HCHO is methanal; CH₃CHO is ethanal.
  • Ketones: replace the e by -one: CH₃COCH₃ is propanone.
  • Carboxylic acids: CH₃COOH is ethanoic acid. Count the carbon in -COOH too.

Worked example: name these compounds

Problem

Name: (a) CH₃CH₂CH₂OH (b) CH₃CH₂CHO (c) CH₃CH₂COOH (d) CH₃CH₂Cl

Working
  1. (a) 3 carbons (prop) and an -OH group (-ol): propanol.
  2. (b) 3 carbons, counting the C of -CHO (prop), and an aldehyde (-al): propanal.
  3. (c) 3 carbons, counting the C of -COOH (prop), and a carboxylic acid (-oic acid): propanoic acid.
  4. (d) 2 carbons (eth) with -Cl as a prefix: chloroethane.
Answer

Propanol, propanal, propanoic acid, chloroethane

In real life

The labels on nail polish remover (propanone, or acetone) and on a bottle of vinegar (ethanoic acid) use these names. IUPAC names mean a chemist in Chennai and one in Tokyo know exactly which compound is meant.

Exam angle

1 marks: “Write the IUPAC name of HC≡C-CH₂-CH₃.” 1-butyne.

2 marks: “Identify the functional group and give the IUPAC name of (i) CH₃CH₂CH₂CHO and (ii) CH₃COCH₂CH₃.” (i) Aldehyde group (-CHO): butanal. (ii) Ketone group (C=O inside the chain): butanone.

3 marks: “Give the IUPAC rules for naming a branched alkane, and use them to name CH₃-C(CH₃)₂-CH₂-CH₂-CH₃.” Choose the longest chain (5 C: pentane); name the side groups (two methyls); number from the end nearer the groups (both on C2); use di for identical groups. Name: 2,2-dimethylpentane.

Remember it

Monkeys Eat Peeled Bananas: meth, eth, prop, but. Then pent, hex, hept, oct.